Answer:
40%
Step-by-step explanation:
Let x = numerator
Let y = denominator

Decreased by 30% = 100% - 30% = 70% = 70/100 = 0.7
Decreased by 50% = 100% - 50% = 50% = 50/100 = 0.5



1.4 as a percentage = 1.4 x 100 = 140%
Therefore, the percentage increase is 140 - 100 = 40%
Using the asymptote concept, we have that:
- The vertical asymptote is x = 9.
- The horizontal asymptote is y = 3.
- The end behavior is that as
.
<h3>What are the asymptotes of a function f(x)?</h3>
- The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
- The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.
In this problem, the function is:

For the vertical asymptote, we have that:
x - 9 = 0 -> x = 9.
For the horizontal asymptote:

Hence, the end behavior is that as
.
More can be learned about asymptotes at brainly.com/question/16948935
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Answer
2nd one
(2,-2) ordered pair -4 y-intercept
Answer:
Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.
The total cost of both games is:
X + Y
We know that both games cost just above AED 80
Then:
X + Y > AED 80
From this, we want to prove that at least one of the games costed more than AED 40.
Now let's play with the possible prices of X, there are two possible cases:
X is larger than AED 40
X is equal to or smaller than AED 40.
If X is more than AED 40, then we have a game that costed more than AED 40.
If X is less than or equal to AED 40, then:
X ≥ AED 40
Now let's take the maximum value of X in this scenario, this is:
X = AED 40
Replacing this in the first inequality, we get:
X + Y > AED 80
Replacing the value of X we get:
AED 40 + Y > AED 80
Y > AED 80 - AED 40
Y > AED 40
So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.
So we proven that in all the possible cases, at least one of the two games costs more than AED 40.