Question

Look at the picture part 1

Answer 1

We are given equation $y = -3x^2$.

We need to check the given table.

We have x=-2,-1,0,1,2 in the given table.

Plugging x=-2,-1,0,1,2 in the given equation

For x=-2

y = -3 (-2)^2 = -3(4) = -12

For x =-1

y = -3 (-1)^2 = -3(1) = -3

For x =-0

y = -3 (0)^2 = -3(0) = 0

For x =1

y = -3 (1)^2 = -3(1) = -3

For x =2

y = -3 (2)^2 = -3(4) = -12.

Therefore, correct table is

  x       y      (x,y)

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 -2   -12       (-2,-12)

 -1    -3        (-1,-3)

  0    0        (0,0)

  1     -3        (1,-3)

  2    -12       (2,-12).

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