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schepotkina [342]
3 years ago
14

What is the surface area of a sphere with a radius of 20 m?

Mathematics
2 answers:
navik [9.2K]3 years ago
8 0
SA=4pir^2
r=20m
SA=4pi20^2
SA=4pi400
SA=1600pi m^2
RideAnS [48]3 years ago
6 0
The formula of surface area of sphere= 4pi*r^2
radius=20 m
S.A=4*pi*20^2
S.A=4*pi*400
S.A=1600 pi m2
so the answer is a 1600 pi m2
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When 5 is added to a set of 3 numbers the mean increases to 4.6. What was the mean of the original 3 numbers?
SVEN [57.7K]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷  Multiply 4.6 by 4 to get the sum of the numbers after 5 was added:

4.6 x 4 = 18.4

^ This is the new total

Subtract 5 from this:

18.4 - 5 = 13.4

Divide this value by 3 to get the original mean:

13.4/3 = 67/15

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7 0
3 years ago
Which point does the graph of the parent function Y=tan(x) pass through?
zvonat [6]

Answer:

(0, 0)

Step-by-step explanation:

The graph of y = tan x passes through the origin, (0, 0).

7 0
3 years ago
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Write the number 4.2 x 10^2 in standard form.
Sav [38]

Answer:

420 (lol)

Step-by-step explanation:

6 0
4 years ago
What is the arc length of an arc with radius 15 inches and central angle 30 degrees
RUDIKE [14]

Answer:

7.855 inches

Step-by-step explanation:

The formula to find the length of an arc is :

Arc Length = \frac{\theta}{360} × 2 π r

Here,

Θ ⇒ size of the angle ⇒ 30°

r ⇒ radius ⇒ 15 inches

<u>Let us solve it now.</u>

Arc length = \frac{\theta}{360} × 2 π r

Arc length = \frac{30}{360}*2*\pi*15

Arc length = \frac{30*2*\pi*15}{360}

Arc length = \frac{2827.8}{360}

Arc length = 7.855 inches

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7 0
2 years ago
A plane flying a straight course observes a mountain at a bearing of 30.3degrees to the right of its course. At that time the pl
Svetllana [295]

Answer:

12km or 12 kilometers

Step-by-step explanation:

We are given the following values:

For the first bearing we have:

30.3 degrees at a distance of 9 kilometers

We are asked to find the second distance of the second bearing at 40.3 degrees

Therefore, we have:

30.3 degrees = 9km

40.3 degrees = ?? Unknown( we designate this as y)

We crossmultiply

30.3 degrees × y = 9km × 40.3 degrees

Divide the both sides by 30.3 degrees

y = (9km × 40.3 degrees) ÷ 30.3 degrees

y = 362.7/30.3 degrees

y = 11.97029703 km

Approximately to the nearest tenth of a km

y = 12km.

Therefore, the distance of the plane from the mountain when the second bearing is taken​ (to the nearest tenth of a​ km) is 12km.

8 0
3 years ago
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