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VashaNatasha [74]
4 years ago
9

Which graph shows the solution to the logarithmic equation below? log3 X =log 0.5 X

Mathematics
1 answer:
lisov135 [29]4 years ago
8 0

Answer:

The answer to this question is A

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What is the slope of a line perpendicular to the line whose equation is Y=2x+5?
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3 years ago
The z-score associated with 95% is 1.96. If the sample mean is 200 and the standard deviation is 30, find the upper limit of the
ziro4ka [17]

Answer:

The upper limit of the 95% confidence interval is:

C.I_u = 200 + (58.8/\sqrt{n})

Step-by-step explanation:

The formula is given as:

C.I = μ ± Z*σ/\sqrt{n}

The upper limit => C.I_u = μ + Z*σ/\sqrt{n}

The lower limit => C.I_l = μ - Z*σ/\sqrt{n}

The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.

The upper limit => C.I_u = 200 + 1.96*(30/\sqrt{n})

                                    = 200 + (1.96*30)/\sqrt{n}

                                    = 200 + 58.8/\sqrt{n}

5 0
3 years ago
EMERGENCY!!PLEASE HELP
Ronch [10]

The more plot point the better but you must have at least three  points, a labeled X-axis and Y-axis, and a table for the data to be organized into.

8 0
4 years ago
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Find the difference -1/10 - 8/10<br><br>-9/10 <br><br>9/10 <br><br>-7/10<br><br> 7/10
TEA [102]

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5 0
4 years ago
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Find the sum of -6/ab + a^2/b^2
Ymorist [56]

Answer:

\frac{1}{ab^{2} } (a³ - 6b)

Step-by-step explanation:

\frac{-6}{ab} + \frac{a^{2} }{b^{2} }

= \frac{-6b + a^{3} }{ab^{2} }

= \frac{1}{ab^{2} } (a³ - 6b)

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