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3 years ago

Use rhombus TQRS below for questions what is the value of x? what is the value of y?

Mathematics

1 answer:

sladkih [1.3K]3 years ago

6 0

The value of x is 1.

The value of y is 4.

Solution:

Given TQRS is a rhombus.

Property of rhombus:

Diagonals bisect each other.

In diagonal TR

⇒ 3x + 2 = y + 1

⇒ 3x – y = –1 – – – – (1)

In diagonal QS

⇒ x + 3 = y

⇒ x – y = –3 – – – – (2)

Solve (1) and (2) by subtracting

⇒ 3x – y – (x – y) = –1 – (–3)

⇒ 3x – y – x + y = –1 + 3

⇒ 2x = 2

⇒ x = 1

Substitute x = 1 in equation (2), we get

⇒ 1 – y = –3

⇒ –y = –3 – 1

⇒ –y = –4

⇒ y = 4

The value of x is 1.

The value of y is 4.

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To find the difference of this problem, start by simplifying the denominator, which will look like $\frac{3}{x+7}-\frac{42}{(x+7)(x-7)}$ . Next, multiply $\frac{3}{x+7}$ by $\frac{x-7}{x-7}$ to create a fraction with a common denominator in order to subtract from $\frac{42}{(x+7)(x-7)}$ . The problem will now look like $\frac{3}{x+7}*\frac{x-7}{x-7}-\frac{42}{(x+7)(x-7)}$ .

Then, simplify the terms in the problem by first multiplying $\frac{3}{x+7}$ and $\frac{x-7}{x-7}$ , which will look like $\frac{3(x-7)}{(x+7)(x-7)}-\frac{42}{(x+7)(x-7)}$ . The next step is to combine the numerators over the common denominator, which will look like $\frac{3(x-7)-42}{(x+7)(x-7)}$ .

Next, simplify the numerator, and to simplify the numerator start by factoring 3 out of $3(x-7)-42$ , which will look like $\frac{3(x-7-14)}{(x+7)(x-7)}$ . Then, subtract 14 from -7, which will look like $\frac{3(x-21)}{(x+7)(x-7)}$ . The final answer will be $\frac{3(x-21)}{(x+7)(x-7)}$ .