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tatiyna
3 years ago
6

What is the decimal multiplier to increase by 93%?

Mathematics
1 answer:
Sidana [21]3 years ago
5 0

Answer:

0.93

Step-by-step explanation:

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7 0
3 years ago
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Solve 12.7 ≥ s − 5.3 Graph the solution.
Julli [10]
Hello!

I dont a graph to show you but I will solve the answer.

12.7 + 5.3 <span>≥ s

18 </span><span>≥ s

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4 years ago
canning operation is designed to fill cans with 14.5 oz of ingredients, on average, with a standard deviation of 0.1 oz. Nine ca
Pavlova-9 [17]

Answer:

SE = 0.025

Step-by-step explanation:

We are given;

Sample mean; x¯ = 14.52

Sample standard deviation; s = 0.075

Sample size; n = 9

Now,formula for standard error of sample mean is;

SE = s/√n

SE = 0.075/√9

SE = 0.075/3

SE = 0.025

3 0
3 years ago
A collection of quarters and dimes is worth $14.90. There are 80 coins in all. Find how many of each there are in the collection
sashaice [31]

The trick here is to relate the NUMBER of coins to each other in one equation, and then the VALUE of the coins in another equation. If I have 1 dime, that 1 dime is worth 10 cents. The number of dimes is obviously not equal to the value. Let's call quarters q and dimes d. The number of these 2 types of coins added together is 80 coins. So q + d = 80. Now, we know that quarters are worth .25 and dimes are worth .1, so we express a quarter's worth as .25q; we express a dime's worth as .1d. The value of the coins we have is 14.90. So that equation is .25q + .1d = 14.90. Let's solve the first equation for q. q = 80 - d. We can now use that as a substitution for q into the second equation, giving us an equation with only 1 unknown, d. .25(80-d) + .1d = 14.90. Distributing through the parenthesis we have 20 - .25d + .1d = 14.90. Combining like terms gives us - .15d = - 5.1. We will divide both sides by - .15 to get that the number of dimes is 34. If we had a total of 80 coins, then the number of quarters is 80 - 34, which is 46. 46 quarters and 34 dimes

7 0
4 years ago
Math question whoever helps get brainly!! 20 points
user100 [1]
The student does not make an error

4 0
4 years ago
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