Answer:
question incomplete.
Step-by-step explanation:
Hi there,
There are 16 members in a math club such as 2 girls and 14 boys in a math club.
The ratio would be:
1:7
Divide both terms by 2.
2 ÷ 2 = 1
14 ÷ 2 = 7
Therefore:
2 : 14 = 1 : 7
Answer: No, the normal curve cannot be used.
Step-by-step explanation:
The theorem of the Normal approximation states that if X is B(n,p) then for large n X is N(np, np(1-p)).
The accuracy of this approximation is good
i. for n > [10/p(1-p)]
ii. p is close to 1/2
Hence given p= 4% = 0.04,
q = 1 - 0.04 = 0.96
Let N = [10/p(1-p)]
We find N = 10/p(1-p) = 10/(0.04× 0.96)
N ~= 260
Since n < 260 and p < 0.5
The approximation is not a good one
Answer:
Step-by-step explanation:
D bc yes
Answer:
<h2>1. x = 4</h2><h2>2. x = 20</h2>
Step-by-step explanation:
1.
ΔABC and ΔAJK are similar (AA). Therefore the sides are in proportion:
We have:
AC = 1 + 4 = 5
AJ = 1
AB = 1 + x
AK = 1
Substitute:
<em>subtract 1 from both sides</em>
2.
ΔVUT and ΔVMN are similar (AA). Therefore the sides are in proportion:
We hve:
VU = x + 8
VM = x
VT = 49
VN = 49 - 14 = 35
Substitute:
<em>cross multiply</em>
<em>use the distributive property a(c + b) = ab + ac</em>
<em>subtract 35x from both sides</em>
<em>divide both sides by 14</em>
