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amid [387]
3 years ago
5

Saitima could take Goku True or false? Be sure to explain your reasoning

Mathematics
1 answer:
Tasya [4]3 years ago
5 0
The correct answer is :False
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Which answer best describes the solution to the equation
SCORPION-xisa [38]
4 + 5z = 5z + 4 is an identity and is true for all values of z.

The equation has, therefore, infinitely many solutions.
3 0
3 years ago
Read 2 more answers
Nicolas sold 86 newspapers on Monday 79 on Tuesday and 68 on Wednesday and 83 on Friday how many newspapers did Nicholas sell on
natima [27]

Answer:

75

Step-by-step explanation:

86+79+68+83=316

391-316=75

8 0
3 years ago
Read 2 more answers
Suppose each of the following data sets is a simple random sample from some population. For each dataset, make a normal QQ plot.
adell [148]

Answer:

a) For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

b) For this case the data is skewed to the left and we can't assume that we have the normality assumption.

c) This last case the histogram is not symmetrical and the data seems to be skewed.

Step-by-step explanation:

For this case we have the following data:

(a)data = c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

We can use the following R code to get the histogram

> x1<-c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

> hist(x1,main="Histogram a)")

The result is on the first figure attached.

For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

(b)data = c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> x2<- c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> hist(x2,main="Histogram b)")

The result is on the first figure attached.

For this case the data is skewed to the left and we can't assume that we have the normality assumption.

(c)data = c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> x3<-c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> hist(x3,main="Histogram c)")

The result is on the first figure attached.

This last case the histogram is not symmetrical and the data seems to be skewed.

7 0
3 years ago
A team of psychologists studied the effect of multitasking on the completion of cognitive tasks. A group of 40 women participate
kakasveta [241]

Answer: Matched-pairs t-test

Step-by-step explanation:

5 0
3 years ago
What is the equation of the line that passes through the points (–12, –8) and (–17, –16)?
Stella [2.4K]
Where is the graph? Upload a picture of the graph first 
7 0
3 years ago
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