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Solnce55 [7]
3 years ago
8

How high is a tree that casts a 28​-ft shadow at the same time that a 6​-ft fence post casts a 8​-ft ​shadow?

Mathematics
1 answer:
Vikentia [17]3 years ago
6 0

Answer: 21 feet.


Step-by-step explanation:

1. You know that the tree casts a 28​ feet shadow and that a 6​ feet fence post casts a 8​ feet ​shadow, then, you can write the following proportion to solve this problem:

\frac{x}{28}=\frac{6}{8}

2. When you solve for the height ot tree (x), you obtain the following result:

x=\frac{28*6}{8}\\x=21

3. Therefore, the height of the tree is 21 feet.


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8.9 x 10^-10 in standard form
Harlamova29_29 [7]

Answer:

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Engineering Notation: 890.0x-12

real number: 8.9E-10

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Step-by-step explanation:

6 0
3 years ago
2x^2=9-3x <br> Find the factors
d1i1m1o1n [39]

Answer:

x = -3, $ \frac{3}{2} $

Step-by-step explanation:

The given quadratic equation is: $ 2x^2 = 9 - 3x $

This can be written as: $ 2x^2 + 3x - 9 = 0 $

To solve a quadratic equation of the form $ ax^2 + bx + c = 0 $ we use the formula:

           $ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $

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Therefore, the roots of the equation are:

$ x = \frac{- 3 \pm \sqrt{9 - 4(2)(-9)}}{2(2)} $

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We get two values of 'x', viz.,

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$ \implies x = \frac{6}{4} \hspace{5mm} \& \hspace{5mm} \frac{-12}{4} $

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Since the factors of the quadratic equation is asked, we write it as:

(x + 3)(x - $ \frac{3}{2} $) = 0

because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.

Multiply (x + 3) and (x - $ \frac{3}{2} $ to see that this indeed is the given quadratic equation.

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Answer:

A. With each 9s fact you add another 9, which means you go straight down a row and back one space. This creates a diagonal pattern in the grid.

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