1)105 divided by 2 equals 52.5
2)294 divided by 6 equals 49 then, 49 times 8 equals 392
3)22 divided by 5 equals 4.4 then, 77 divided by 4.4 equals 17.5
the correct question is
<span>The length of a rectangle is represented by 4a + 3b, and its width is represented by 3a-2b. Write a polynomial for the perimeter of the rectangle. What is the minimum perimeter of the rectangle if a=12 and b is a non-zero </span>whole number?
we know that
Perimeter of a rectangle=2*[length + width]
length=(4a+3b)
width=3a-2b
so
P=2*[(4a+3b)+(3a-2b)]-----> P=2*[7a+b]-----> P=14a+2b
the answer part a) is
A polynomial for the perimeter of the rectangle is P=14a+2b
Part b)
for a=12
P=14*12+2b---------> P=168+2b
<span>the minimum perimeter of the rectangle is for b=1
</span>so
P=168+2*1-----> P=170 units
the answer part b) is
the minimum perimeter of the rectangle is 170 units
W= width
l= length= 2w-3
Area= length * width
A= lw
substitute l=2w-3 for l
54= (2w-3)(w)
54= 2w^2 - 3w
subtract 54 from both sides
0= 2w^2 - 3w - 54
factor the polynomial
0= (2w + 9)(w - 6)
Set each set of parentheses equal
to 0 and solve for width.
0=2w+9
-9=2w
-4.5= w NEGATIVE VALUE
0=w-6
6 cm=w
-4.5 is not the answer because it has a negative value. You cannot have a negative side of a photograph. So substitute 6 in to find length.
length= 2w-3
l= 2(6)-3
l= 12-3
l= 9 cm
CHECK:
w= 6cm
l= 9cm
Area= length * width
54= 6*9
54= 54
ANSWER: width= 6cm; length= 9cm
Hope this helps! :)
Personally if I would of put it in a fraction it be 2/10
