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Ray Of Light [21]
3 years ago
11

The two-way table below displays demographic data for the passengers aboard the Titanic.

Mathematics
2 answers:
zimovet [89]3 years ago
6 0

Answer: 0.72

Step-by-step explanation: Trust me, I had it on KHAN Academy

meriva3 years ago
5 0

Answer:

About 72%

Step-by-step explanation:

All you have to do is divide the number of children who traveled in third class (79) by the total number of children (109)

79/109=.724770642 OR 72%

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Volume of the cone is 100 in³

Step-by-step explanation:

  • Step 1: Volume of a cone = 1/3 πr²h. Find volume of the cone where r = 3 inches and h = 9 inches.

Volume = 1/3 × 3.14 × 3² × 9

             = 84.78 in³ ≈ 100 in³ (rounding off to nearest hundredth)

6 0
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100pts HELP asap divide fractions
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6 1/13 for sure
5 14/13 -> 79/13
79/13 to mixed number is 6 1/13
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Find the ratio of the students who study French to students who do not study French give your answer in its simplest form
Vlad1618 [11]
(2/5) of (2/3) of students = 4/15 of students study French. Then 1-(4/15) = 11/15 of students do not study French. The ratio you want is
  (4/15):(11/15) = 4:11

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In a math expression "of" means "times".
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3 years ago
A ball is dropped from a height of 10 feet and returns to a height that is one half of the height from which it fell
Alexandra [31]

Answer:

5ft

Step-by-step explanation:

5 0
3 years ago
When grading an exam, 90% of a professor's 50 students passed. If the professor randomly selected 10 exams, what is the probabil
Damm [24]

Using the binomial distribution, it is found that there is a:

a) 0.9298 = 92.98% probability that at least 8 of them passed.

b) 0.0001 = 0.01% probability that fewer than 5 passed.

For each student, there are only two possible outcomes, either they passed, or they did not pass. The probability of a student passing is independent of any other student, hence, the binomial distribution is used to solve this question.

<h3>What is the binomial probability distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 90% of the students passed, hence p = 0.9.
  • The professor randomly selected 10 exams, hence n = 10.

Item a:

The probability is:

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.9)^{8}.(0.1)^{2} = 0.1937

P(X = 9) = C_{10,9}.(0.9)^{9}.(0.1)^{1} = 0.3874

P(X = 10) = C_{10,10}.(0.9)^{10}.(0.1)^{0} = 0.3487

Then:

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1937 + 0.3874 + 0.3487 = 0.9298

0.9298 = 92.98% probability that at least 8 of them passed.

Item b:

The probability is:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

Using the binomial formula, as in item a, to find each probability, then adding them, it is found that:

P(X < 5) = 0.0001

Hence:

0.0001 = 0.01% probability that fewer than 5 passed.

You can learn more about the the binomial distribution at brainly.com/question/24863377

3 0
2 years ago
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