Answer:
Below.
Step-by-step explanation:
We can write an odd integer as 2x + 1 so consecutive odd digits would be 2x + 1 and 2x + 3, so the equation is:
2x + 1 + 2x + 3 = 156
4x + 4 = 156 can be used to solve for x and find the integers.
4x = 152
Dividing through by 4:
x = 152/4 = 38
So the 2 integers are 2(38) + 1 and 2(38) + 3
= 77 and 79.
Answer:
1/11
Step-by-step explanation:
12 + 8 + 2
22 / 2
1/11
There is always a pair of socks... A pair is 2. Add everything and divide it.
Hope this helps....
Answer:
x = -1 or 2
Step-by-step explanation:
Taking the antilog, you have the quadratic ...
x^2 -x -1 = 1
x^2 -x -2 = 0 . . . . subtract 1
(x -2)(x +1) = 0 . . . factor
The values of x that make these factors zero are the solutions to the equation.
x = 2 or x = -1
Only two real numbers satisfy x² = 23, so A is the set {-√23, √23}. B is the set of all non-negative real numbers. Then you can write the intersection in various ways, like
(i) A ∩ B = {√23} = {x ∈ R | x = √23} = {x ∈ R | x² = 23 and x > 0}
√23 is positive and so is already contained in B, so the union with A adds -√23 to the set B. Then
(ii) A U B = {-√23} U B = {x ∈ R | (x² = 23 and x < 0) or x ≥ 0}
A - B is the complement of B in A; that is, all elements of A not belonging to B. This means we remove √23 from A, so that
(iii) A - B = {-√23} = {x ∈ R | x² = 23 and x < 0}
I'm not entirely sure what you mean by "for µ = R" - possibly µ is used to mean "universal set"? If so, then
(iv.a) Aᶜ = {x ∈ R | x² ≠ 23} and Bᶜ = {x ∈ R | x < 0}.
N is a subset of B, so
(iv.b) N - B = N = {1, 2, 3, ...}
Answer:lol thanks
Step-by-step explanation:
