Answer:
61.22m
Explanation:
Maximum height in projectile is expressed as;
H = u²sin²θ/2g
u is the speed
g is the acceleration due to gravity
θ is the angle of projection
Substitute the given values into the formula;
H = u²sin²θ/2g
H = 40²sin²60/2g
H = 1600(0.8660)²/2(9.8)
H = 1600(0.8660)²/2(9.8)
H = 1,199.9/19.6
H = 61.22m
Hence the maximum height achieved by the ball is 61.22m
Answer:
A: 1.962
B: 3.924
Explanation:
g = G *M /R^2
g = 9.807*M/R^2 the gravitational constant of ground level on earth is about 9.807
g = 9.807*5lbs/R^2 the average brick is about 5 pounds.
g = 9.807*5*10^2. I'm assuming the height is around ten feet to help you out.
with these numbers plugged in you get an acceleration of 0.4905 a final velocity after 4 seconds 1.962. It's height fallen after 4 seconds is 3.924.
( M = whatever the brick weighs it's not specified in the question)
(R = the distance from the ground or how high the scaffold is)
(hopefully you can just plug your numbers in there hope this helps)
Answer:
- your body moving forwards when sudden brakes/force is applied e.g. sudden braking in a car
- feeling a backwards force when something moves quickly from rest e.g a bus
- when you stir a cup of tea, it continues to swirl for a short period of time even though you have stopped
- when shaking a tree, it's leaves or fruit fall down
- satellites which move due to the inertia of motion
hope this helped :)
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I HOPE IT HELPS