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max2010maxim [7]
3 years ago
7

The diagram below shows a golf ball being struck by a club. The ball leaves the club with a speed of 40 meters per second at an

angle of 600 with the horizontal. Calculate the maximum height achieved by the ball.
Physics
1 answer:
hjlf3 years ago
4 0

Answer:

61.22m

Explanation:

Maximum height in projectile is expressed as;

H = u²sin²θ/2g

u is the speed

g is the acceleration due to gravity

θ is the angle of projection

Substitute the given values into the formula;

H = u²sin²θ/2g

H = 40²sin²60/2g

H = 1600(0.8660)²/2(9.8)

H = 1600(0.8660)²/2(9.8)

H = 1,199.9/19.6

H = 61.22m

Hence the maximum height achieved by the ball is 61.22m

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faust18 [17]

Substract two consecutive terms of the sequence to see if there is a common difference:

\begin{gathered} (-3)-(3)=-3-3=-6 \\ (-9)-(-3)=-9+3=-6 \\ (-15)-(-9)=-15+9=-6 \end{gathered}

As we can see, there is a common difference of -6.

Then, if a number of the sequence is given, the next one can be found by adding -6 (which is the same as subtracting 6).

Notice that the first term of the sequence is 3.

Then, the rule for the sequence is to start with 3 and add -6 repeatedly.

Therefore, the correct choice is option A) Start with 3 and add -6 repeatedly.

7 0
2 years ago
A concrete block (B-36 x10 °C-') of volume 100 mat 40°C is cooled to
ruslelena [56]
  • T1=40°C=313K
  • T_2=-10°C=263K

Applying Charles law

\\ \sf\Rrightarrow \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

\\ \sf\Rrightarrow \dfrac{100}{313}=\dfrac{V_2}{263}

\\ \sf\Rrightarrow V_2=\dfrac{26300}{313}

\\ \sf\Rrightarrow V_2=84.02ml

6 0
2 years ago
Consider the speed of light in another universe to be only 100 m/s. Two cars are traveling along a highway in opposite direction
olganol [36]

Answer:

-62.45m/s and +62.45m/s

Explanation:

The formula for relativistic speed

This is the speed of A with respect to B

V_{AB}=\frac{V_{A}-V_{B}}{1-\frac{V_{A}V_{B}}{C^2} }

where

V_{A} will be the velocity of person 1: 39m/s

V_{B} will be the velocity of person 2: -31m/s (negative because is travelling in opposite direction)

and C the velocity of light: 100m/s

The velocity of person 1 measured by person 2 is:

V_{AB}=\frac{39m/s-(-31m/s)}{1-\frac{(39m/s)(-31m/s)}{(100m/s)^2}}=62.45m/s

The velocity of person 2 measured by person 1 is:

V_{BA}=\frac{V_{B}-V_{A}}{1-\frac{V_{B}V_{A}}{C^2} }

V_{BA}=\frac{-31m/s-39m/s}{1-\frac{(-31m/s)(39m/s)}{(100)^2} }=-62.45m/s

8 0
3 years ago
You are going 30 m/s in a car of mass 1000 kg when you reach a red light and stop your car.
Radda [10]

Answer:

Explanation:

The kinetic energy will convert to heat energy (provided the car has friction brakes and not regenerative brakes as might be found on an electric or hybrid) Also<u> assuming level road</u>.

E = ½mv² = ½(1000)30² = 450,000 J

5 0
2 years ago
A young man walks daily through a gridded city section to visit his girlfriend, who lives m blocks East and nblocks North of whe
Arada [10]

Answer:

The man ate eggs.

Explanation:

He should brush his teeth before seeing his girlfriend.

4 0
3 years ago
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