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QveST [7]
3 years ago
15

Four different vehicles are shown. Assume that all four vehicles are traveling at the same speed on a highway. Which is true abo

ut the kinetic energy of the vehicles?
A. The motorcycle has the most kinetic energy because it has the least mass.

B. All of the vehicles have the same kinetic energy because they are moving at the same speed.

C. The delivery van has the greatest kinetic energy because its mass is greater than that of the other
vehicles.

D. The delivery van has the greatest kinetic energy because it has the most tires in contact with the
pavement.

Physics
1 answer:
klasskru [66]3 years ago
6 0

Answer:

Option C. The delivery van has the greatest kinetic energy because its mass is greater than that of the other

vehicles.

Explanation:

Kinetic energy is the energy of an object in motion. Mathematically, it is expressed as:

K.E = ½mv²

Where:

K.E is the kinetic energy.

m is the mass of the object.

v is the velocity of the object.

From the formula above, we can say that:

Kinetic energy is directly proportional to the mass of the object and the square of the velocity of the object. This simply means that objects with higher mass will have a greater kinetic energy than objects will lighter mass even if their velocities are the same.

From the question given above, it is obvious that the delivery van has a greater mass than the rest object.

Therefore, the delivery van will have the greatest kinetic energy because its mass is greater than that of the other

vehicles.

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Each of the four expansion models (recollapsing, critical, coasting, and accelerating) predict different ages for the universe,
cupoosta [38]

Answer:

This is because the age of the universe is determined by the pace of expansion in the past, and each model forecasts a different pace.

Explanation:

The age of the universe is determined by the pace of expansion in the past, and each model forecasts a different pace.

This is due to the fact that the expansion rate in the coasting model is constant and never changes. Because the cosmos is growing faster now than during the old days, recollapsing and critical models give shorter ages. According to the accelerating model, the universe is growing at a slower rate currently than in the past, implying an older age.

4 0
3 years ago
A spaceship starting from a resting position accelerates at a constant rate of 9.8 meters per second per second. How long and ho
Verizon [17]

Accelerating at 9.8 m/s² means that every second, the speed is 9.8 m/s faster than it was a second earlier.  It's not important to the problem, but this number (9.8) happens to be the acceleration of gravity on Earth.

1% of the speed of light = (300,000,000 m/s) / 100 = 3,000,000 m/s .

Starting from zero speed, moving (9.8 m/s) faster every second,
how long does it take to reach  3,000,000 m/s ?

           (3,000,000 m/s) / (9.8 m/s²)  =  306,122 seconds .
                                                   (That's  5,102 minutes.)
                                                        (That's  85 hours.)
                                                     (That's  3.54 days.)

Speed at the beginning . . . zero .
Speed at the end . . . 3,000,000 m/s
Average speed . . . . . 1,500,000 m/s

Distance = (average speed) x (time)

               = (1,500,000 m/s) x (306,122 sec) = 4.592 x 10¹¹ meters

                                                                     =  459 million kilometers

                         That's like from Earth
                                                  to       Sun
                                                             to    Earth
                                                                    to        Sun. 

4 0
3 years ago
- How long does it take a packet of length 1,000 bytes to propagate over a link of distance 2,500 km, propagation speed 2.5 *10^
Sunny_sXe [5.5K]

Answer:

It will take 0.01 s or 10 ms

Solution:

As per the question:

Length of the packet, L = 1,000 bytes = 1000\times 8 = 8000 bits

Distance, d = 2500 km = 2.5\times 10^{6}\ m

Speed of propagation, s = 2.5\times 10^{8}\ m/s

Transmission rate, R = 2 Mbps

Now,

Propagation time, t can be calculated as:

t = \frac{d}{s} = \frac{2.5\times 10^{6}}{2.5\times 10^{8}} = 0.01\ s

t = 10 ms

  • In general, propagation time, t is given by:

       t = \frac{link\ distance}{Propagation\ speed}

  • No, this delay is independent of the length of the packet.
  • No, this delay is independent of the rate of transmission.

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It mainly depends on the season of the year 
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