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oksian1 [2.3K]
3 years ago
15

If logc81=2 l o g c 81 = 2 , what is the value of c c ?

Mathematics
1 answer:
Alexxx [7]3 years ago
8 0
<span>If logc81=2 then c=9

</span>
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When a fraction of 17 is taken away from 17 what remains exceeds 1/3 of 17 by 6
MrRissso [65]
1/3×17/1=51/1

51+6=57
4 0
3 years ago
Consider the function f(x)=xln(x). Let Tn be the nth degree Taylor approximation of f(2) about x=1. Find: T1, T2, T3. find |R3|
Fynjy0 [20]

Answer:

R3 <= 0.083

Step-by-step explanation:

f(x)=xlnx,

The derivatives are as follows:

f'(x)=1+lnx,

f"(x)=1/x,

f"'(x)=-1/x²

f^(4)(x)=2/x³

Simialrly;

f(1) = 0,

f'(1) = 1,

f"(1) = 1,

f"'(1) = -1,

f^(4)(1) = 2

As such;

T1 = f(1) + f'(1)(x-1)

T1 = 0+1(x-1)

T1 = x - 1

T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2

T2 = 0+1(x-1)+1(x-1)^2

T2 = x-1+(x²-2x+1)/2

T2 = x²/2 - 1/2

T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3

T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3

T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)

Thus, T1(2) = 2 - 1

T1(2) = 1

T2 (2) = 2²/2 - 1/2

T2 (2) = 3/2

T2 (2) = 1.5

T3(2) = 1/6 (-2^3 + 6 *2^2 - 3 *2 - 2)

T3(2) = 4/3

T3(2) = 1.333

Since;

f(2) = 2 × ln(2)

f(2) = 2×0.693147 =

f(2) = 1.386294

Since;

f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).

Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,

Since;

f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2

Finally;

R3 <= |2/(4!)(2-1)^4|

R3 <= | 2 / 24× 1 |

R3 <= 1/12

R3 <= 0.083

5 0
3 years ago
Which choice is equivalent to the quotient below? √64/√4<br>a. √2<br>b. √4/4<br>c. √8/2<br>d. 4​
Ksju [112]

Step-by-step explanation:

you did not even try a calculator to find the result ?

64 is 8×8 or 8².

so, sqrt(64) = 8.

similarly for 4 :

4 is 2×2 or 2².

so, sqrt(4) = 2

so,

sqrt(64)/ sqrt(4) = 8 / 2 = 4

so, d. is the right answer.

4 0
2 years ago
-3(x – 14) + 9x = 6x + 4<br>​
8090 [49]

Answer:

there are no solutions :3

no this is not a joke sjsjsj there are equations who has an answer and ones that are impossible to have a solution. use the no solution sign when you answer it or sum

Step-by-step explanation:

6 0
3 years ago
Solve the inequality and graph its solution: 6n – 11 &gt; 31
miss Akunina [59]
<span>6n – 11 > 31
</span><span>6n  > 31 + 11
</span>6n  > 42
  n > 42/6
  n > 7
5 0
3 years ago
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