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butalik [34]
2 years ago
10

Help I will give u 5 point please someone

Mathematics
1 answer:
galben [10]2 years ago
6 0
Using Pythagorean Theorem 9 to the second is 81 and 3 to the second is 9 ... u add those two together it’s 90 and take the square root of that and it’s 9.48 round that as the question asked?
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PLEASE HELP THIS IS DUE IN 1 HOUR!! I CAN GIVE BRAINLIEST! ILL GIVE 20 POINTS TOO!
inessss [21]

Answer:

The radius of the inner circle is 14 ft. Since the outer circle is 3 ft more than the inner circle, its radius is 17 ft. The circumference formula is 2(pi)radius (or 2(22/7)17 in this case). The circumference of the outer circle is 106.85 ft (or 106.9 if rounding). To find the difference, you would subtract the smallest FROM the greatest:

106.85 - 88 = 18.85 ft (or 18.9 if rounding)

8 0
2 years ago
Read 2 more answers
Can someone plssss helpp me with this!!! and show the work!
hichkok12 [17]

Answer:

1/2

Step-by-step explanation:

8(1/2)^4

= 8 * 1 / 2^4

= 8/(2*2*2*2)

= 8/16

= (8*1) / (8*2)

= 1/2

5 0
2 years ago
Find the area of quadrilateral ABCD
andreev551 [17]

Answer:

<em>A ≈ 28.5</em>

Step-by-step explanation:

a, b, c

P = a + b + c

Semiperimeter s = \frac{a+b+c}{2}

A = \sqrt{s(s-a)(s-b)(s-c)}

~~~~~~~~~~~~~~~

P_{ABC} = 4.3 + 2.89 + 6.81 = 14

s = 14 ÷ 2 = 7

A_{ABC} = \sqrt{7(7-4.3)(7-2.89)(7-6.81)} = √14.75901 ≈ 3.84

P_{BCD} = 8.59 + 7.58 + 6.81 = 22.98

s = 22.98 ÷ 2 = 11.49

A_{BCD} = \sqrt{11.49(11.49-8.59)(11.49-7.58)(11.49-6.81)} = √609.7343148 ≈ 24.6928

A_{ABCD} = 3.84 + 24.6928 ≈ <em>28.5</em>

3 0
2 years ago
The ratio of the width to the height of a window is 2:7. The width of the window is 3ft. Write and solve a proportion to find th
poizon [28]
10.5 -- 3/2=1.5 -- 7x1.5=10.5
5 0
3 years ago
PLEASE HELPPP
balu736 [363]
DI’m pretty sure it’s
6 0
3 years ago
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