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butalik [34]
3 years ago
10

Help I will give u 5 point please someone

Mathematics
1 answer:
galben [10]3 years ago
6 0
Using Pythagorean Theorem 9 to the second is 81 and 3 to the second is 9 ... u add those two together it’s 90 and take the square root of that and it’s 9.48 round that as the question asked?
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Help with 1-9 , please!!!!
murzikaleks [220]
1. 160
You just add normally.
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If you are struggling you can use a website called ixl it cost money but it can really help a lot !
4 0
3 years ago
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Use the net to find the lateral area of the prism. 15 m 3 m 6 m 3 m 6 m
postnew [5]

Answer:

270 m²

Step-by-step explanation:

LA = (3+6+3+6)×15

= 18×15 = 270 m²

5 0
3 years ago
A bucket of paint has spilled on a tile floor. The paint flow can be expressed with the function p(t) = 6t, where t represents t
Neko [114]

Answer:

A)   A[p(t)] = 36πt²

B)   7234.56 square units

Step-by-step explanation:

               

<u>Given functions</u>:

\begin{cases}p(t)=6t \\ A(p)=\pi p^2 \end{cases}

<u>Part A</u>

To find the area of the circle of spilled paint as a function of time, substitute the function p(t) into the given function A(p):

\begin{aligned}A(p) & = \pi p^2\\\\ \implies A[p(t)] & = \pi [p(t)]^2\\& = \pi (6t)^2\\& = \pi 6^2 t^2\\& = 36\pi t^2\end{aligned}

<u>Part B</u>

Given

  • t = 8 minutes
  • π = 3.14

Substitute the given values into the equation for A[p(t)} found in part A:

\begin{aligned}A[p(8)] & = 36\pi t^2\\& = 36 \cdot 3.14 \cdot 8^2\\& = 36 \cdot 3.14 \cdot 64\\& = 113.04 \cdot 64\\& = 7234.56\:\: \sf square\:units\end{aligned}

Therefore, the area of spilled paint after 8 minutes if 7234.56 square units.

4 0
2 years ago
Read 2 more answers
Need help with this problem please !!
Harrizon [31]

Answer:

2

Step-by-step explanation:

30y x 2 = 60y

3 0
3 years ago
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A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 402 gram setting. It is
lidiya [134]

Answer:

The value of t test statistics is -2.25.

Step-by-step explanation:

We are given that a manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 402 gram setting. It is believed that the machine is under filling the bags.

A 25 bag sample had a mean of 393 grams with a standard deviation of 20.

<u><em>Let </em></u>\mu<u><em> = mean filling of bags by the machine.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 402 gram     {means that the the machine is not under filling the bags}

Alternate Hypothesis, H_A : \mu < 402 gram     {means that the the machine is under filling the bags}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean bag filling = 393 grams

            s = sample standard deviation = 20 grams

            n = sample of bags = 25

So, <u><em>test statistics</em></u>  =  \frac{393-402}{\frac{20}{\sqrt{25} } }  ~ t_2_4

                               =  -2.25

The value of t test statistics is -2.25.

5 0
3 years ago
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