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butalik [34]
3 years ago
10

Help I will give u 5 point please someone

Mathematics
1 answer:
galben [10]3 years ago
6 0
Using Pythagorean Theorem 9 to the second is 81 and 3 to the second is 9 ... u add those two together it’s 90 and take the square root of that and it’s 9.48 round that as the question asked?
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It may be can be number 1 (a)
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A quiz consists of 6 multiple choice questions.each question has 4 possible answers.a student is unprepared and guess answers by
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<span>Thus, simply compute the probabilities for 4,5,6,7 as well, and then add. Alternatively, you can compute the probabilities for 0,1,2 correct answers, and subtract the total from 1, giving the same result. </span>
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Find all of the roots of the equation.
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I think it's letter C.

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Prove the identity (cosx+cosy)^2+(sinx-siny)^2= 2+2cos(x+y)
astra-53 [7]
(cos(x) + cos(y))^2 + (sin(x) - sin(y))^2 Remove the brackets

cos^2(x)
+ cos^2(y) + 2cos(x)*cos(y) + sin^2(x) - 2(sin(x)*sin(y) + sin^2(y) Combine these two in bold to make 1 because sin^2(x) + cos^2(x) = 1

1 + cos^2(y) + 2cos(x)*cos(y) - 2*sin(x)*cos(y) + sin^2(y) 
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2 + 2cos(x)*cos(y) - 2*sin(X)*sin(y) Bring out a common factor of 2
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but cos(x+y ) = cos(x)*cos(y) - sin(x)*sin(y)

2 + 2* cos(x + y) is your final answer. 

4 0
3 years ago
Read 2 more answers
Please help please these are short answers
atroni [7]

Answer: The answers are given below.


Step-by-step explanation:  The calculations are as follows:

(19) Weight of the puppy last week is

W_\ell=2\dfrac{1}{2}~\textup{lb},

and weight of the puppy this week is

W_p=7\dfrac{1}{4}=\dfrac{29}{4}~\textup{lb}.

Therefore, the weight gained by the puppy is given by

W_g=W_p-W_\ell=\dfrac{29}{4}-\dfrac{5}{2}=\dfrac{29-10}{4}=\dfrac{19}{4}=4\dfrac{3}{4}~\textup{lb}.

(20) Time taken in Route 1 = 1 hour 30 minutes.

Time taken in Route 2 = 1 hour 45 minutes.

Time taken in Route 3 = 1 hour 35 minutes.

Time taken in Route 4 = 1 hour 25 minutes.

Since we want to spent the least amount of time on the bus, so we will be taking route 4.

(21) Time taken by Nazia to complete her language arts homework is

H_\ell=\dfrac{4}{9}~\textup{hr},

and the time taken by Nazia to complete her Mathematics homework is

H_m=\dfrac{2}{9}~\textup{hr}.

Therefore, Nazia takes more time to complete Language Arts homework, by

H=H_\ell-H_m=\dfrac{4}{9}-\dfrac{2}{9}=\dfrac{2}{9}~\textup{hr}.

(22) Quantity of Aluminium collected by Maya is

A_m=\dfrac{4}{20}=0.2~\textup{lb},

and the quantity of Aluminium collected by her friend Abigail is

A_a=\dfrac{7}{8}=0.87~\textup{lb}.

Therefore,

(a) Abigail collected more aluminium

and

(b) Total Aluminium collected by both the girls is

T=A_m+A_a=\dfrac{4}{20}+\dfrac{7}{8}=\dfrac{8+35}{40}=\dfrac{43}{40}~\textup{lb}.

(23) Quantity of snow fall last Wednesday is

S_w=3\dfrac{1}{4}=3.25~\textup{in.},

and quantity of snowfall on sunday is

S_s=3\dfrac{4}{5}=3.8~\textup{in.}.

Therefore, quantity of snowfall was more on Sunday by

S=S_s-S_w=3\dfrac{4}{5}-3\dfrac{1}{4}=\dfrac{19}{5}-\dfrac{13}{4}=\dfrac{76-65}{20}=\dfrac{11}{20}~\textup{in.}.

Thus, all the questions are answered.

3 0
3 years ago
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