3 years ago

Find the equation of a line that passes through the points (1,-5) and (3,-6).

Mathematics

1 answer:

Paha777 [63]3 years ago

7 0

Answer:

y = -1/2x +11/2

Step-by-step explanation:

slope finding: -5+6/1-3 = -1/2

equation making: y+5 = -1/2(x-1)

rearranging: y = -1/2x +11/2

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Find x and y, given that KL and line MN are parallel. Show all work

Setler [38]

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$\dfrac{|MK|}{|KJ|}=\dfrac{|NL|}{|LJ|}\\\\\dfrac{x-2}{5}=\dfrac{12}{8}\ \ \ \ |cross\ multiply\\\\8(x-2)=5\cdot12\\\\8x-16=60\ \ \ |+16\\\\8x=76\ \ \ |:8\\\\\boxed{x=9.5}$

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3 years ago

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4 years ago

One more then im done, ty ^^

OleMash [197]

Answer:

Step-by-step explanation: