Four less than the quotient of a number and 3 is -10
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By applying the equation of dilation, the coordinates of the vertices of the triangle ABC are A'(x, y) = (-12, 0), B'(x, y) = (0, -9) and C'(x, y) = (-12, -9).
<h3>How to find the image of a triangle</h3>
A dilation is a type of <em>rigid</em> transformation. <em>Rigid</em> transformations are transformations applied to <em>geometric</em> loci such that <em>Euclidean</em> distances are conserved.
There is a triangle and its image must be a triangle, the <em>new</em> triangle is found by transforming the three vertices of the prior one following this formula:
A'(x, y) = P(x, y) + k · [A(x, y) - P(x, y)] (1)
Where:
- P(x, y) - Center of reflection.
- A(x, y) - Original vertex
- A'(x, y) - New vertex
- k - Dilation factor
If we know that P(x, y) = (0, 0), A(x, y) = (-4, 0), B(x, y) = (0, -3) and C(x, y) = (-4, -3), then the new vertices of the triangle are, respectively:
Point A
A'(x, y) = (0, 0) + 3 · [(-4, 0) - (0, 0)]
A'(x, y) = (-12, 0)
Point B
B'(x, y) = (0, 0) + 3 · [(0, -3) - (0, 0)]
B'(x, y) = (0, -9)
Point C
C'(x, y) = (0, 0) + 3 · [(-4, -3) - (0, 0)]
C'(x, y) = (-12, -9)
Lastly, we draw the two triangles, which are presented in the image attached below.
To learn more on dilations: brainly.com/question/13176891
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so the characteristic solution is
As a guess for the particular solution, let's back up a bit. The reason the choice of
Now the ODE in terms of
Of coursesin, the characteristic equation will be
Now that we have two linearly independent solutions, we can easily find more via variation of parameters. If
where
and recalling that