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ch4aika [34]
3 years ago
12

In a bag there are 40 pieces of candy: 7

Mathematics
2 answers:
Sonja [21]3 years ago
8 0
The answer is 13/40
Slav-nsk [51]3 years ago
3 0

Answer:

37.5

Step-by-step explanation:

because if you calculte percent = to 37.5 that is why it sis the correct answer

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The sum of two digit numbers is 14 when you reverse its digits you increase the number by 36 what is the number
Dmitry_Shevchenko [17]
10x+y = 10y+x +36
x+y=14

9x-9y=36
x-y=4

x= 14-y
14-2y==4
10=2y
y=5
x=9
7 0
3 years ago
Sharon is drawing up a plan for building a reduced Eiffel Tower on her backyard patio. She has room to make a base of 5 feet. He
BaLLatris [955]

Answer:

it is A

Step-by-step explanation

4 0
3 years ago
Read 2 more answers
Evaluate the expression for the given value of x.<br> 3x + 4 for x= 5
pantera1 [17]
Answer:
19

Explanation:
3x+4
Plug in 5 as x
3(5)+4
=15+4
=19

I hope this helps!
7 0
3 years ago
The smallest object visible with your eyes is similar to the width of a piece of hair, which is 1×10−4 meters wide. Using an opt
Sloan [31]

Answer:

B. 5\times10^{2}

Step-by-step explanation:

We are told that the smallest object visible with our eyes is similar to the width of a piece of hair, which is 1\times 10^{-4} meters wide.

Using an optical microscope, we can see items up to 2\times 10^{-7} meters wide.

To find the objects we can see with our eyes are how much larger than the objects we can see with an optical microscope, we can set an equation as:

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1*10^{-4}}{2*10^{-7}}

Using the exponent rule of quotient \frac{a^m}{a^n}=a^{m-n} we will get,

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1}{2}*10^{-4-(-7)}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{-4+7}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{3}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10\times 10^{3-1}

\text{The object we can see with our eyes}=5\times10^{2}*\text{The objects we can see with microscope}

Therefore, the objects we can see with our eyes are 5\times10^{2} times larger than the objects we can see with an optical microscope and option B is the correct choice.

3 0
3 years ago
The radius of a circle is decreasing at a rate of 6.56.56, point, 5 meters per minute. At a certain instant, the radius is 12121
Ilia_Sergeevich [38]

Answer:

The rate of change of the area of the circle is  approximately -490.09 \ m^2/min.

Step-by-step explanation:

Given:

\frac{dr}{dt} = -6.5 \ m/min

radius r =12 \ m

We need to find the rate of change of the area of the circle at that instant.

Solution:

Now we know that;

Area of the circle is given by π times square of the radius.

framing in equation form we get;

A= \pi r^2

to find the rate of change of the area of the circle at that instant we need to take the derivative on both side.

\frac{dA}{dt}=\frac{d(\pi r^2)}{dt}\\\\\frac{dA}{dt}= 2\pi r \frac{dr}{dt}

Substituting the given values we get;

\frac{dA}{dt}= 2\times \pi \times 12 \times -6.5\\\\\frac{dA}{dt}\approx -490.09 \ m^2/min

Hence The rate of change of the area of the circle is  approximately -490.09 \ m^2/min.

6 0
3 years ago
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