Should be somewhere around there either way for 9. the angles are the same because you see the arrows on the parallel lines 8. I'm not quite as sure about
Which of the following is not a triangle congruence theorem? A. ASA B. AAS C. SSA
1 answer:
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Answer:
The correct option is;
C. 3. ∠BDE ≅∠BAC, Corresponding Angles Postulate 4. ∠B ≅ ∠B Reflexive Property of Equality
Step-by-step explanation:
The two column proof can be written as follows;
Statement, Reason
1. , Given
2. is a transversal , Conclusion from statement 1.
We note that ∠BDE and ∠BAC are on the same side of the transversal relative to the parallel lines, and are therefore, corresponding angles.
Therefore, we have;
3. ∠BDE ≅∠BAC, Corresponding Angles Postulate
Also
4. ∠B ≅ ∠B, Reflexive Property of Equality
In the two triangles, ΔABC and ΔDBE, we have ∠BDE ≅∠BAC and ∠B ≅ ∠B,
From ∠BDE + ∠B + ∠BED = 180°
∠BAC + ∠B + ∠BCA = 180°
Therefore, ∠BED = ∠BCA Substitution property of equality
Which gives;
5, ΔABC ~ ΔDBE, Angle Angle Similarity Postulate
6. BD/BA = BE/BC, Converse of the Side-Side-Side Similarity Theorem
First of all, let's find the slope of line L. To find the slope of a line, you write it in the explitic form , and consider the coefficient
. So, we have
So, the slope of line L is 2/3.
Two lines are parallel if they have the same slope. So, line M has slope 2/3 as well, and we know that it passes through the point (3, -10).
When you are given the slope and a point
of a line, its equation is given by
So, if you plug your values, you have
which you can simplify into