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3 years ago

The annual percentage rate on a credit card determines

Business

1 answer:

Digiron [165]3 years ago

6 0

My answer -

it determines how much they charge you in interest if you carry a balance. Lower is better. The percentage interest is what they charge you each month, “annual percentage rate” is what you’re paying if you keep that balance for a year. It’s slightly different because in that year, you’re also paying interest on the amount of interest (compound interest) you owe in the previous months.

Not carrying a balance means that you don’t pay interest.

p.s

Let me know if you need anymore help on brainly so I can help you again. Have an AWESOME!!! day :^)

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Which of the following insurgency elements do the actual fighting and provide security?

Drupady [299]

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3 years ago

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3 years ago

Which of the following steps is NOT a basic step followed by PERT and CPM?

vodomira [7]

Answer:

Explanation:

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-Develop relationships among the activities.

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3 years ago

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Dominik [7]

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3 years ago

Suppose 20.0 g pieces of gold and iron, both initially at 100oC, are added to different containers of water, both initially at 2

Sauron [17]

Answer:

The final temperature in the container with Gold is 27.49 ⁰C

The final temperature in the container with Iron is 33.01 ⁰C

Therefore, the highest final temperature is obtained in the container with Iron.

Explanation:

Q = mcΔT

Where;

Q is the quantity of heat gained or lost

m is the mass of the metals or water

c is the specific heat capacity

ΔT is the change in temperature, T₂ - T₁

T₂ is the final temperature and T₁ is the initial temperature

Heat lost by metals at 100°C is equal to heat gained by water at 25°C

$-Q_{metal} = Q_{water}$

$-Q_{Au} = Q_{H_2O} \\-Q_{Fe} = Q_{H_2O}$

Specific heat capacity of water = 4.18 J/g°C

Specific heat capacity of gold = 0.129 J/g°C

Specific heat capacity of iron = 0.45 J/g°C

⇒For Gold

-20*0.129*(T₂ - 100) = 18*4.18 (T₂ - 25)

-2.58T₂ +258 = 75.24T₂ - 1881

77.82T₂ = 2139

T₂ = 2139/77.82

T₂ = 27.49 ⁰C

⇒For Iron

-20*0.450*(T₂ - 100) = 18*4.18 (T₂ - 25)

-9T₂ +900 = 75.24T₂ - 1881

84.24T₂ = 2781

T₂ = 2781/84.24

T₂ = 33.01 ⁰C

Therefore, the highest final temperature is obtained in the container with Iron.

5 0

3 years ago