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aev [14]
3 years ago
11

Hundreds = 130 tens = ones

Mathematics
1 answer:
valina [46]3 years ago
3 0
13 hundreds = 130 tens = 1300 ones
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(2x^9y^n) (4x²y^10)-8x^11 y^20                        i say the answer 1 or 10

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

1

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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(2x^9y^n) (4x²y^10)-8x^11 y^20

1

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(2x^9y^n) (4x²y^10)-8x^11 y^20

1

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(2x^9y^n) (4x²y^10)-8x^11 y^20

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4 0
2 years ago
Which number produces an irrational number when multiplied by 1/3
MArishka [77]

We can simply observe that.

  1. 0.777... is rational, because it is a number with infinite but repeating decimal part.
  2. 1/3 is rational, because it's the division between two integers
  3. -\sqrt{16}=-4, so this is rational as well.

Since the product of two rational numbers is always rational, we have that

0.\bar{7}\cdot \dfrac{1}{3},\quad \dfrac{1}{3}\cdot \dfrac{1}{3},\quad -4\cdot \dfrac{1}{3}

are all rationals, since they are the product of two rationals.

On the other hand, we have

\sqrt{27}=\sqrt{9\cdot 3}=3\sqrt{3}

and thus

3\sqrt{3}\cdot \dfrac{1}{3}=\sqrt{3}

which is irrational.

3 0
3 years ago
Plz answer and provide an explanation
riadik2000 [5.3K]

I believe it is A and Yes

The bigger the price is on an item, the more tax you would have to pay, so both numbers increase. As for whether or not there is a line through the dots, you use a line when you could go inbetween the points. For example, with this question you can have 0.24, 0.86, or any other number as the price and it would make sense. If the question was sales tax on a certain number of shirts, well, you can't buy half a shirt so you don't need anywhere inbetween the dots.

Proportional in these kinds of problems means whether or not the line curves. If it doesn't and is a straight line, then it is proportional.

8 0
3 years ago
The minimum value of f(x) = x3 – 3x2 – 9x + 2 on the interval [–4, 0] is
garri49 [273]

Answer:

-74

Step-by-step explanation:

Graph the function. See attached picture. Between the interval where -4 > x < 0, the graph rises up to a peak and descends back down when x = 0. This means the minimum value will be where x = -4.

Substitute x = -4 into the equation.

f(-4) = (-4)^3 -3(-4)^2 - 9(-4) + 2

f(-4) = -64 -3(16) +36 + 2

f(-4) = -64 - 48 + 36 + 2

f(-4) = -74

5 0
3 years ago
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