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2 years ago

Hundreds = 130 tens = ones

Mathematics

1 answer:

valina [46]2 years ago

3 0

13 hundreds = 130 tens = 1300 ones

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Mustafa buys a book that costs $12.50 if the sales tax is 8% what is the total cost of the book

wariber [46]

The total cost of the book would be:

12.50* 0.8= 10

The total cost of the book would be $10.00

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3 years ago

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If f(x) = 3x2 + 2 and g(x) = x2 – 9, find (f – g)(x).

hoa [83]

Answer:

2x^2 +11

Step-by-step explanation:

f(x) = 3x^2 + 2 and g(x) = x^2 – 9

(f – g)(x) = 3x^2 + 2 -( x^2 – 9)

Distribute the minus sign

3x^2 + 2 - x^2 + 9

Combine like terms

2x^2 +11

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2 years ago

How to write 1.075 in two foarms

tangare [24]

1 75/1000

One and seven thousandth

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2 years ago

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Sheldon picked 4 4/10 kg but 15 kg were rotten and had to be thrown away. How many kilograms of tomatoes were not rotten?

nataly862011 [7]

Answer:

10.6 kg

Step-by-step explanation:

first convert 4 4/10 to kg

4/10 is equal to .4

so 4.4kg were rotten

subtract from total

15-4.4=10.6 kg

3 0

2 years ago

A hog producer is feeding soybean meal and corn to his pigs. He needs to know how many pounds he needs to feed of each in order

Mazyrski [523]

Answer:

Feed 1, Soybean meal required = $\dfrac{2000}{3} \text{ lbs.}$

Feed 2, Corn meal required = $\dfrac{4000}{3} \text{ lbs.}$

Step-by-step explanation:

Total feed is 1 ton i.e. 2000 lbs.

Let x be the amount of Feed 1 required.

Feed 1 has $45\%$ of protein.

$\text{Protein in Feed 1 = }x \times \dfrac{45}{100} ..... (1)$

Then, amount of Feed 2 required = $(2000 - x) \text{ lbs.}$

Feed 2 has $15\%$ of protein.

$\text{Protein in Feed 2 = }(2000 - x) \times \dfrac{15}{100} ..... (2)$

As per question, total protein required is $25\%$ of 2000 lbs .

Adding (1) and (2) and putting it equal to total protein required.

$\Rightarrow x \times \dfrac{45}{100} + (2000 - x) \times \dfrac{15}{100} = 2000 \times \dfrac{25}{100}\\\Rightarrow 45x + 30000 - 15x = 50000\\\Rightarrow 30x = 20000\\\Rightarrow x = \dfrac{2000}{3}$

Feed 1 required = $\dfrac{2000}{3}\text{ lbs .}$

Feed 2 required = $2000 - \dfrac{2000}{3}\\$

$\Rightarrow \dfrac{4000}{3}\text{ lbs.}$

7 0

3 years ago