Answer:
what is the question??
Step-by-step explanation:
Answer:
The Proof for
Part C , Qs 9 and Qs 10 is below.
Step-by-step explanation:
PART C .
Given:
AD || BC ,
AE ≅ EC
To Prove:
ΔAED ≅ ΔCEB
Proof:
Statement Reason
1. AD || BC 1. Given
2. ∠A ≅ ∠C 2. Alternate Angles Theorem as AD || BC
3. ∠AED ≅ ∠CEB 3. Vertical Opposite Angle Theorem.
4. AE ≅ EC 4. Given
5. ΔAED ≅ ΔCEB 5. By A-S-A congruence test....Proved
Qs 9)
Given:
AB ≅ BC ,
∠ABD ≅ ∠CBD
To Prove:
∠A ≅ ∠C
Proof:
Statement Reason
1. AB ≅ BC 1. Given
2. ∠ABD ≅ ∠CBD 2. Given
3. BD ≅ BD 3. Reflexive Property
4. ΔABD ≅ ΔCBD 4. By S-A-S congruence test
5. ∠A ≅ ∠C 5. Corresponding parts of congruent Triangles Proved.
Qs 10)
Given:
∠MCI ≅ ∠AIC
MC ≅ AI
To Prove:
ΔMCI ≅ ΔAIC
Proof:
Statement Reason
1. ∠MCI ≅ ∠AIC 1. Given
2. MC ≅ AI 2. Given
3. CI ≅ CI 3. Reflexive Property
4. ΔMCI ≅ ΔAIC 4. By S-A-S congruence test
Answer: 20 feet perimeter is the largest allowed
Step-by-step explanation: width=2.5 length=no more than 3x2.5
so find longest possible length allowed...
2.5x3=7.5
calculate largest perimeter allowed...
2(7.5+2.5)=20
Answer:
52
Step-by-step explanation:
sorry if it's wrong
Answer:
190 square foot
Step-by-step explanation:
School yard = 950 square foot
20% of school yard for student to start garden
Therefore
20/100 x 950
= 190 square foot
