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Natalija [7]
3 years ago
11

g(x)= ​4−3x ​ ​8 ​​ g, left parenthesis, x, right parenthesis, equals, start fraction, 8, divided by, 4, minus, 3, x, end fracti

on h(y)=\dfrac{2y-9}{5}h(y)= ​5 ​ ​2y−9 ​​ h, left parenthesis, y, right parenthesis, equals, start fraction, 2, y, minus, 9, divided by, 5, end fraction (h\circ g) (4)=(h∘g)(4)=left parenthesis, h, circle, g, right parenthesis, left parenthesis, 4, right parenthesis, equals
Mathematics
1 answer:
siniylev [52]3 years ago
7 0

Answer:

(h\circ g)(4)=-\dfrac{11}{5}

Step-by-step explanation:

Given: g(x)=\dfrac{8}{4-3x}

h(y)=\dfrac{2y-9}{5}

To find: (h\circ g)(4)

It is composite function (hog)(x) and to find the value at x=4

We can write (hog)(4) as h(g(4))

(hog)(4)=h(g(4))

Now, we find g(4)

g(4)=\dfrac{8}{4-3\cdot 4}

g(4)=\dfrac{8}{4-12}

g(4)=\dfrac{8}{-8}

g(4)=-1

Put g(4) into h(y)

h(g(4))=\dfrac{2\cdot g(4)-9}{5}

h(g(4))=\dfrac{2\cdot -1-9}{5}

h(g(4))=\dfrac{-2-9}{5}

h(g(4))=-\dfrac{11}{5}

Hence, The value of composite function is -\dfrac{11}{5}

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Answer:

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Step-by-step explanation:

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\text{Put the coordinates of the point to the equation.}\ x=2,\ y=3:\\\\3=\dfrac{1}{3}(2)+b\\\\3=\dfrac{2}{3}+b\qquad\text{subtract}\ \dfrac{2}{3}\ \text{from both sides}\\\\b=2\dfrac{1}{3}

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3 years ago
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Why? First find angle BCA because that angle is on a straight line with another angle on the other side you can do
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Given that :

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2 years ago
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