Algebra 2 find the solution of the equation using a method of your choice

Mathematics

1 answer:

garri49 [273]3 years ago

5 0

Take the 28 and tern it into -28 and do it on both sides, -28 + 28 = 0, -28 + -1 = -30.

Sence x represents one aka any number you will add x with 11 and you will get 12x^2

Now you have to divide 12 on both sides, 12 divided by 12 is 1 so it eliminates it, 12 divided by -30 = -2.5, so then X = -2.5, and that should be right

I hope this helps! =)

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tatuchka [14]

Answer:

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Tanya [424]

So we just do
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4 0

3 years ago

Which is the simplified form of the expression ((p squared) (q Superscript 5 Baseline)) Superscript negative 4 Baseline times ((

Alexus [3.1K]

Answer:

$q^{-30}$

Step-by-step explanation:

Given the expression:

$((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}$

First, we open the outer brackets

$=(p^{2X-4}) (q ^{5X-4})X (p ^{-4X-2}) (q^{5X-2})\\\\=(p^{-8}) (q ^{-20})X (p ^{8}) (q^{-10})\\\\$Next, we can collect like terms\\\\=p^{-8}Xp ^{8}Xq ^{-20}Xq ^{-10}\\\\$Applying addition law of indices\\\\=p^{-8+8}Xq^{-20+(-10)}\\\\=p^0 X q^{-30}\\\\=1 X q^{-30}\\\\=q^{-30}$