$\implies 2^{2x}-2\cdot5^{2x}-(2^x)(5^x)>0$
let $2^x=a$ and $5^x=b$
So, $a^2-2b^2-ab>0$
divide by $b^2$, ($b^2>0$)
$\implies \left(\frac ab\right)^2-\left(\frac ab\right) -2>0$
this is a quadratic, in $\left(\frac ab\right)$, let it be $x$
So, $x^2-x-2>0$
Can you simplify it now?
V = lwh
15(10.5)(4.5) = 708.75
Answer:
After 6 hours, one, and one half inches of rain is expected
Step-by-step explanation:
1/4*6=1 1/2
35/-7 = -5 +6 = 1<----- Answer
$253600÷4:7
253600÷4/7=443800
The answer is $443800.
I didn't understand the question so I did this. I'm sorry if it doesn't help.
