All the following are valid Excel arithmetic operators except D (>). caret(^), asterisk(*), percent(%) and plus/minus (+,-) signs are all arithmetic. Letter D the greater than and less than sign(<, >) is a comparison operators where you compare two values using greater/less than signs.
Answer:
#include <iostream>
using namespace std;
int main()
{
int input = 0;
int count = 0;
int sum = 0;
int sumNegative = 0;
while (true) {
cout << "Enter a number: ";
cin >> input;
if (input == 0) break;
count++;
sum += input;
if (input < 0) {
sumNegative += input;
}
}
cout << "Count of the numbers: " << count << endl;
cout << "Sum of all the numbers: " << sum << endl;
cout << "Sum of the negative numbers: " << sumNegative << endl;
}
Explanation:
Your requirements regarding the sum and the negative numbers was a bit vague so I just did something you can probably adjust easily to your liking.
<u>Answer:</u>
<u>Cloud computing</u><em> allow the user to access software or any document from the remote place.</em>
<u>Explanation:</u>
Let us understand what does the word cloud actually means. In simple terms, we get rain from cloud, but we don’t know actually which cloud burst to give rain.
In a similar way, <em>the cloud computing is the concept of storing files in multiple servers and multiple location</em> and it provide access when the <em>client needs the source. </em>
Cloud computing enable user to work on <em>software online</em> or to download document or <em>edit / create documents online</em>. Certain services are <em>free and few other are paid.</em>
Solution :
x = float_(input())
y = float_(input())
z = float_(input())
res1 = x**z
res2 = x**(y**z)
res3 = abs(x-y)
res4 = (x**z)**0.5
print('{:.2f} {:.2f} {:.2f} {:.2f}'.format(res1,res2,res3,res4))
Output is :
5.0
1.5
3.2
172.47 361.66 3.50 13.13
Answer: yeah i mean i use my canon camera
Explanation:
