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2 years ago

9x + 26 + 7x - 17 = 2x + (-3x) + 5x

Mathematics

1 answer:

slega [8]2 years ago

4 0

9x + 26 + 7x - 17 = 2x + (-3x) + 5x =
16x + 9 = 2x - 3x + 5x =
16x + 9 = 4x
9 = 4x - 16x
9 = - 12x
-9/12 = x
- 3/4 = x

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2 years ago

G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =

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Given:

The two functions are:

$g(b)=5b-9$

$h(b)=(b-1)^2$

To find:

The value of $(h\circ g)(-6)$ .

Solution:

We have,

$g(b)=5b-9$

$h(b)=(b-1)^2$

We know that,

$(h\circ g)(b)=h(g(b))$

$(h\circ g)(b)=h(5b-9)$

$(h\circ g)(b)=[(5b-9)-1]^2$

$(h\circ g)(b)=[5b-10]^2$

Putting $b=-6$ , we get

$(h\circ g)(-6)=[5(-6)-10]^2$

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3 years ago

-2/3- (-3/4) Simplify if needed Brainliest Also, 5/6+5/12

bazaltina [42]

Answer:

$-\frac{2}{3} - (-\frac{3}{4}) = \frac{1}{12}$

$\frac{5}{6} + \frac{5}{12} = \frac{5}{3}$

Step-by-step explanation:

Given

$-\frac{2}{3} - (-\frac{3}{4})$

Required

Solve:

$-\frac{2}{3} - (-\frac{3}{4})$

Open bracket

$-\frac{2}{3} - (-\frac{3}{4}) = -\frac{2}{3} +\frac{3}{4}$

Take LCM

$-\frac{2}{3} - (-\frac{3}{4}) = \frac{-8+9}{12}$

$-\frac{2}{3} - (-\frac{3}{4}) = \frac{1}{12}$

$\frac{5}{6} + \frac{5}{12}$

Take LCM

$\frac{5}{6} + \frac{5}{12} = \frac{10+5}{12}$

$\frac{5}{6} + \frac{5}{12} = \frac{15}{12}$

Divide by 3/3

$\frac{5}{6} + \frac{5}{12} = \frac{5}{3}$

4 0

3 years ago