All categories

3 years ago

Solve 20p−60 using GCF

Mathematics

1 answer:

ExtremeBDS [4]3 years ago

7 0

Greatest common factor between each term is 20, so you'd divide both by 20 to reduce this to 20(p - 3).

You might be interested in

Please help me multiple choice at top

vlabodo [156]

Answer:

A translation of 4 units up and 4 units to the left is the correct answer.

8 0

3 years ago

-18, 10, -20, -11, 9, 18 Mean Median Mode Range

Vlada [557]

Mean = -2

Median = -1

Mode = Nil

Range = 38

Step-by-step explanation:

Given data is:

-18, 10, -20, -11, 9, 18

Arranging the data in ascending order

-20, -18, -11, 9, 10, 18

Mean:

Mean is given by the formula

$Mean=\frac{Sum}{items}$

Items are: 6

$Mean = \frac{-20-18-11+9+10+18}{6}\\= \frac{-12}{2}\\= -2$

Mode:

Mode is the most frequent value in the data. So,

As there is no value repeated in the data. There is no mode

Median:

Median is the middle value of the data. As the no. of data value are even,

the average of middle 2 values is mode.

Note that the data has to be arranged in ordered to find median

Here,

$Median = \frac{-11+9}{2}\\=\frac{-2}{2}\\= -1$

Range:

Range is the difference between the largest and smallest value of the data

Here

Largest value = 18

Smallest value = -20

So,

$Range = Largest\ value-Smallest value\\= 18-(-20)\\= 18+20\\=38$

Hence,

Mean = -2

Median = -1

Mode = Nil

Range = 38

Keywords: Data, Median

Learn more about statistics at:

#LearnwithBrainly

3 0

3 years ago

A system with 6 independent components is such that the system will fail if at least one of the individual components fail. the

Ipatiy [6.2K]

The components operate independently, so the probability of "total" system failure is the same as the product of each probability of component failure. That is, if $A_i$ denotes the event that component $i$ fails, then

$\mathbb P(A)=\mathbb P(A_1\cup\cdots\cup A_6)=\mathbb P(A_1)\times\cdots\times\mathbb P(A_6)$

The $A_i$ are independent and identically distributed, so $\mathbb P(A_i)=\mathbb P(A_j)$ for all $i,j$ . So

$\mathbb P(A)=\mathbb P(A_1)^6=0.02^6=6.4\times10^{-11}=0.000000000064$

7 0

3 years ago

What is a reasonable estimate for the problem 3 3/4 x (- 2/5) a.-2 b.-1/2 c.1/2 d.2

kolezko [41]

Answer:

a. -2

Step-by-step explanation:

3¾ ≈ 4

-⅖≈ -½

4 × (-½) = -2

A reasonable estimate is -2.

3 0

3 years ago

Read 2 more answers

1. Which is the best definition of a proper fraction?

Tju [1.3M]

Answer:

C. A Fraction whose Numerator is smaller than the denominator

Step-by-step explanation:

A proper fraction is a fraction whose numerator is smaller than its denominator.

An improper fraction is a fraction whose numerator is equal to or greater than its denominator.

Example:

3/4, 2/11, and 7/19 are proper fractions, while 5/2, 8/5, and 12/11 are improper fractions.

3 0

3 years ago