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3 years ago

In what situation might you have to calculate the surface area of volume of a solid?

1 answer:

8 0

One application of volume is determining the density of an object. Assume the object is made of a pure element (eg: gold). If we know the volume (v) of the object, and we know the mass (m), then we can use the formula D = m/v to figure out the density D. Knowing the volume is also handy to determine if the object can fit into a larger space or not. Another application is figuring out how much water is needed to fill up the inner space of the 3D solid (assuming it's hollow on the inside).

The surface area is handy to figure out how much material is needed to cover the outer surface. This material can be paint, paper, metal sheets, or whatever you can think of really. A good example is wrapping a present and the assumption is that there is no overlap.

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You are given that cos(A)=−35, with A in Quadrant II, and cos(B)=817, with B in Quadrant I. Find cos(A−B). Give your answer as a

neonofarm [45]

cos (A - B) is 36/85

<h3>How to simply the identity</h3>

Expand cos(A - B) with the identity

You get, cos(A - B) = cos(A) cos(B) + sin(A) sin(B)

Since A is in quadrant II, so sin(A) > 0,

B is in quadrant I, so sin(B) > 0.

Using the Pythagorean identity, we get

cos²(A) + sin²(A) = 1

Make sin A the subject of formula

$sin(A)^{2}$ = ( $\sqrt{(1 - (-3/5}$ )²)

Find the square root of both sides, square root cancels square

$sin A$ = 4/5

Repeat the same for the second value

$sin A^{2} = \sqrt{(1- 8/17)^2}$

$sin A$ = 15/17

Substitute values into cos(A - B)

cos(A - B) = cos(A) cos(B) + sin(A) sin(B) = (-3/5) * 8/17 + 4/5 * 15/17

cos (A - B) = 36/85

Therefore, cos (A - B) is 36/85

Learn more about trigonometric identities here:

brainly.com/question/7331447

#SPJ1

3 0

2 years ago

Read 2 more answers

If (2-3) + (x + y) = 6, what is x + yl?

Stella [2.4K]

Answer:

Step-by-step explanation:

2-3 = -1 and 7 - 1 is 6

x+y=7

6 0

3 years ago

Help in pic ANYONE??

Advocard [28]

Gs umm 222 x 666 the woods on bay bay and I =372828

7 0

3 years ago

Determine the equation of the joint value

slega [8]

$\bf \qquad \textit{direct proportional variation}\\\\
\begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
\\
&& y={{ k }}x
\end{array}\\\\
-----------------------------\\\\$

$\bf \textit{x varies directly with y and z}\implies x=\underline{k}yz\qquad \underline{k}=
\begin{array}{llll}
constant\ of\\
variation
\end{array}
\\\\\\
\textit{we also know that }
\begin{cases}
x=120\\
y=5\\
z=8
\end{cases}\implies 120=k(5)(8)\implies \cfrac{120}{5\cdot 8}=k
\\\\\\
\boxed{3=k}\qquad thus\implies x=\underline{3}yz
\\\\\\
\textit{now what's "x" when }
\begin{cases}
y=6\\
z=2
\end{cases}\implies x=3(6)(2)$

8 0

4 years ago

Consider the two-factor model with interaction

Digiron [165]

Answer:

Step-by-step explanation: see attachment below

3 0

4 years ago