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Maurinko [17]
3 years ago
11

calculate the distance between the two points shown on the graph below give your answer correct to 2 decimal places if necessary

Mathematics
1 answer:
GenaCL600 [577]3 years ago
4 0

Answer:

Find the distance between (-1, 1) and (3, 4).

This problem is solved simply by plugging our x- and y-values into the distance formula:

D=(3−(−1))2+(4−1)2−−−−−−−−−−−−−−−−−−√=

=16+9−−−−−√=25−−√=5

Sometimes you need to find the point that is exactly between two other points. This middle point is called the "midpoint". By definition, a midpoint of a line segment is the point on that line segment that divides the segment in two congruent segments.

If the end points of a line segment is (x1, y1) and (x2, y2) then the midpoint of the line segment has the coordinates:

(x1+x22,y1+y22)

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I need help . Plz help me
Gekata [30.6K]
The mean is the same thing as the average. To find the average, add all the numbers up (aka find the sum of the numbers) and divide by how many numbers there is:
average =  \frac{sum \: of  \: numbers}{\# \:  of  \: numbers}

So the sum of your numbers is: -6 + 2 + 5 + -7 + -11 + -6 = -23. And there are 6 numbers total.
That means average =  \frac{-23}{6} = -3.833333 ≈ -3.8

Your final answer is -3.8
5 0
4 years ago
Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)
USPshnik [31]

First, expand the terms inside the bracket you will get

(( \tan {}^{2} (x)  + 2 \tan(x)  \sin(x)  +  \sin {}^{2} (x)  - ( \tan {}^{2} (x)  - 2 \tan(x)  +  \sin {}^{2} (x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

( 4 \tan(x)  \sin(x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x)  \sin {}^{2} (x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x) (1 -  \cos {}^{2} (x) ) = 16 (\tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan {}^{2} (x)  -   \frac{  \sin {}^{2} (x) \cos {}^{2} ( {x}^{} )  }{ \cos {}^{2} (x) }

16( \tan {}^{2} (x)  -  \sin {}^{2} (x) ) = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

5 0
2 years ago
♡♡♡please help ♡♡♡<br>thank you ​
ElenaW [278]

Answer:

acute angle

Step-by-step explanation:

<h2><em><u>Finding the angle </u></em></h2>

an obtuse angle is an angle which is more than 90° but less than 180°

a right angle is 90°

a straight angle is 180°

an acute angle is less than 90°

is you look at the picture and the definitions you can notice that the angle is less than 90 ° hence its an <u>acute angle </u>

7 0
3 years ago
Read 2 more answers
Let m = X^2 + 3.
Tpy6a [65]

The Equation in terms of m, m^2+7m+10=0

What is substituting in the equation ?

substituting means changing or replacing the values in the given equation.

Calculation:

Given equation is (x^2+3)^2+7x^2+21=-10

            and m= X^2 + 3.

make the given equation in the form X^2 + 3,

             now,

                     (x^2+3)^2+7x^2+21=-10

                     (x^2+3)^2+7(x^2+3)=-10

             where,

                      X^2 + 3= m

              after putting the value or replacing the values

             we get, m^2+7m=-10

                      m^2+7m+10=0

          the above equation is in the form of "m".

The Equation in terms of m, m^2+7m+10=0

Leran more about substitution here:

brainly.com/question/24094293

#SPJ1

4 0
2 years ago
How to simplify this?
olchik [2.2K]
-2x cube + 2x cube makes 0, so u can delete it,
then 6x + 10x makes 16x,
so the final answer should be 16x+7xtothepower4
5 0
4 years ago
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