Can anyone help me if so Ty no file answers please.
1 answer:
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Answer:
Step-by-step explanation:
This car follows a line, hence its motion can be modeled by the Line equation.
In fact, we already have two points of the line, if we call the time in hours and
the traveled distance in miles:
Point 1:
Since we are told the car's initial position is 300 miles in the time 0 h
Point 2:
Since we are told the car's final position is 180 miles after 3h
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<u>Let's find the Slope :
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This is the slope of the line
Now, the equation of the line is:
We already know the slope, now we have to find the intersection point with the y-axis () with any of the given points. Let's choose Point 1:
Isolating :
Then, the equation of the line is:
check the picture below
Answer:
OBC= 15
OCR =30
In OBQ
OBQ + QOB + OQB = 180
OBQ= OBC=15
OQB= 90
SO, QOB = 180- OBQ- OQB
= 180-15 -90
= 75
c) is correct
