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3 years ago

15

Let the random variable X denote the number of network blackouts in a day. The

1 answer:

faltersainse [42]3 years ago

6 0

E(X) = 0(0.7) + 1(0.2) + 2(0.1) = 0.2 + 0.2 = 0.4
The expected daily loss due to blackouts = 0.4 * $500 = $200

Var(X) = 0(0.7 - 0.4)^2 + 1(0.2 - 0.4)^2 + 2(0.1 - 0.4)^2 = 0.04 + 0.18 = 0.22
The expected daily variance due to blackouts = 0.22 * $500 = $110

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The area of a rectangular rug is given by the trinomial r squared minus 4 r minus 77r2−4r−77. What are the possible dimensions o

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3 years ago

Read 2 more answers

ms salinas is packing lunches for a field trip. She is placing 15 sack lunches in each of 3 ice chests. Each sack lunch contains

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Answer:18

Step-by-step explanation:

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3 years ago

Last tuesday evening, Aaron, the car wash owner, found he had 90% more quarters than dimes. If the combined value of Aaron's qua

Alex Ar [27]

Aaron the car wash owner had 228 quarters and 120 dimes.

<h3>Equation</h3>

An equation is an expression used to show the relationship between two or more variables and numbers.

Let x represent the number of quarters and y represent the number of dimes. Hence:

x = 90% of y + y

x = (0.9y) + y

x - 1.9y = 0 (1)

Also:

0.25x + 0.1y = 69 (2)

From both equations:

x = 228, y = 120

Aaron the car wash owner had 228 quarters and 120 dimes.

Find out more on Equation at: brainly.com/question/13763238

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2 years ago

The difference between x and 6 is less than 14

UNO [17]

Answer:

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3 years ago

The average income, I, in dollars, of a lawyer with an age of x years is modeled with the following function: I = -425x^2 + 45,5

lord [1]

We are given

The average income, I, in dollars is

$I=-425x^2+45500x-650000$

(a)

now, we are given

average income is $275000

so, $I=275000$

now, we can set them equal

and then we can solve for x

$275000=-425x^2+45500x-650000$

$-425x^2+45500x-925000=0$

we will have to use quadratic formula

$x=\frac{-45500+\sqrt{45500^2-4\left(-425\right)\left(-925000\right)}}{2\left(-425\right)}:\quad \frac{-\sqrt{45500^2-1572500000}+45500}{850}$

$x=\frac{-45500-\sqrt{45500^2-4\left(-425\right)\left(-925000\right)}}{2\left(-425\right)}:\quad \frac{\sqrt{45500^2-1572500000}+45500}{850}$

we get

$x=27.28199$

$x=79.776$

we need to find youngest age

It means that we need to choose smallest value

so,

$x=27$ ............Answer

(b)

we are given

x=40

so, we can plug it and find I

$I=-425(40)^2+45500(40)-650000$

$I=490000$ ..............Answer

6 0

3 years ago