The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
<h3>What is the least number of buses needed to carry 710 passengers? </h3>
Given that;
- Number of passengers n = 710
- Least number of buses need B = ?
To get the least number of buses, we say;
Number of buses B = 710 ÷ 150
Number of buses B = 4.7 ≈ 5
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
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Answer:
m<1 and m<2 are obviously congruent so if m<2 is 25 then that means m<1 is also 25
Answer:
1989xsquared y + 585xsquared+ 2618xy + 770x - 8075y - 2375
Step-by-step explanation:
(9x + 25) x (13x - 19) x (17y + 5)
(117x squared - 171x + 325x - 475) x (17y + 5)
(117x squared + 154x - 475) x (17y + 5)
They both have a lab not eh twelfth day because 4,8,12 And then 3,9,12
Answer:
900÷65 = 13.86
Step-by-step explanation:
you'll put the answer how is needed