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3 years ago

Is an isosceles trapezoid below x=

Mathematics

1 answer:

Talja [164]3 years ago

7 0

Answer:

180 degrees

Step-by-step explanation:

you need to add everything up to get 180 hope this helps

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!!!HELP!!!

matrenka [14]

Answer: C. Parabola

Definition: a parabola is a conic section in which it is mostly characterised of having a U-shape wherein it is symmetrical and an open plane curve.

5 0

1 year ago

PLS HELP ME WITH THIS !!

Mashutka [201]

Part 1:
180 = 5p+98 + 9p-2
180 = 14p + 96
84 = 14p
6 = p

part 2:
angle S will be the same as angle Q, so:
9p-2
9(6)-2
54-2
M

3 0

2 years ago

432 tk. is divided amongst three workers A, B and C such that 8 times A's share is equal to 12 times B's share wich is equal to

Flura [38]

Answer:

A got 243 tk

Step-by-step explanation:

Supose the amount C got was "x"

12 times B's share is 6 times C's share, that would be:

B = 6x

Also, 8 times A's share is 12 times B's share, that would be:

8A = 12B

8A = 12(6x)

8A = 72x

A = 72x/8

A = 9x

Now, we can say:

A = 9x

B = 6x

C = x

We know total is 432, thus we can write and solve for x first:

A + B + C = 432

9x + 6x + x = 432

16x = 432

x = 432/16

x = 27

A got "9x", so plugging in x = 27, we know:

A got 9*27 = 243 tk

7 0

3 years ago

A water storage tank has the shape of a cylinder with diameter 14 ft. It is mounted so that the circular cross-sections are vert

andrezito [222]

Answer:

percentage of the total capacity is 75.6%

Step-by-step explanation:

Hello! To solve this problem we follow the following steps

1. draw the complete scheme of the problem (see attached image)

2. To solve this problem we must find the area of the circular sector using the following equation.(c in the second attached image)

$A=\frac{R^2}{2} (\alpha -sin\alpha )$

$\alpha =2arccos(\frac{d}{R})$

3. observing the attached images we replace the values in the equations and find the area of the circular sector, remember that you must transform the angle to radians

$\alpha =2arccos(\frac{5}{7})=88.83$

$A=\frac{R^2}{2} (\alpha -sin\alpha )\\A=\frac{7^2}{2} (88.83-sen88.83)*\frac{\pi rad}{180} =37.57ft^2$

4.we calculate the area of the total circle (At), then subtract the area of the circular sector (Ac) to find the area occupied by water (Aw)

$At=\frac{\pi }{4} (14ft)^2=153.93ft^2$

Aw=At-Ac=153.93-37.57=116.36ft^2

5.Finally, we calculate the percentage that represents the water in the tank by dividing the area of the water over the total area of the tank

$\frac{116.36}{153.93} *100=75.6$

percentage of the total capacity is 75.6%

3 0

3 years ago

Please Help me with these 2 questions!!

qaws [65]

Answer:

3) Parabola

4) $y = 5x^2 + 7$ and $y = \frac{10}{x} +20$

4 0

2 years ago

Read 2 more answers