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True [87]
3 years ago
6

f(x) = |x| and g(x) = |x| + 3 The translation applied to get the graph of g(x) from the graph of f(x) is .

Mathematics
2 answers:
babunello [35]3 years ago
6 0

Answer: Vertical translation of 3 units.

Step-by-step explanation:

Since when a function translated k units vertically then , then the new function becomes H(x)=h(x)+k.

We are given that f(x) = |x| and g(x) = |x| + 3 .

That means the graph of f(x) is translated by 3 units vertically .

Hence, the translation applied to get the graph of g(x) from the graph of f(x) is "Vertical translation of 3 units."

Furthermore it can be seen by the graph below.

murzikaleks [220]3 years ago
4 0

Answer:

a vertical translation of 3 units upward

Step-by-step explanation:

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T(r+4)=28 solve for t<br><br>pls help ​
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Let X = the number of nonzero digits in a randomly selected 4-digit PIN that has no restriction on the digits. What are the poss
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Answer:

X = {0, 1, 2, 3, 4}

Step-by-step explanation:

If X is the number of nonzero digits in a 4-digit PIN with no restriction on the digits, the pin can have up to 4 nonzero digits.

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If the PIN is 0000 then X = 4

If the PIN is 2045 then X = 3

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2 years ago
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2 years ago
Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of
fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given :  the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Since, given the difference of the squares of the numbers is 5 that is (x^2-y^2)^2=5

And the product of the numbers is 6 that is xy=6

Using identity, we have,

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

Substitute, we have,

(x^2+y^2)^2=(5)^2+(2(6))^2

Simplify, we have,

(x^2+y^2)^2=25+144

(x^2+y^2)^2=169

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

5 0
2 years ago
Read 2 more answers
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