Answer:
Dion needs to add 10% of the solution
Answer:
the two possibilities are either 35.5m orrr 65m
Step-by-step explanation:
Check the picture below.
let's recall that a kite is a quadrilateral, and thus is a polygon with 4 sides
sum of all interior angles in a polygon
180(n - 2) n = number of sides
so for a quadrilateral that'd be 180( 4 - 2 ) = 360, thus
![\bf 3b+70+50+3b=360\implies 6b+120=360\implies 6b=240 \\\\\\ b=\cfrac{240}{6}\implies b=40 \\\\[-0.35em] ~\dotfill\\\\ \overline{XY}=\overline{YZ}\implies 3a-5=a+11\implies 2a-5=11 \\\\\\ 2a=16\implies a=\cfrac{16}{2}\implies a=8](https://tex.z-dn.net/?f=%5Cbf%203b%2B70%2B50%2B3b%3D360%5Cimplies%206b%2B120%3D360%5Cimplies%206b%3D240%20%5C%5C%5C%5C%5C%5C%20b%3D%5Ccfrac%7B240%7D%7B6%7D%5Cimplies%20b%3D40%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Coverline%7BXY%7D%3D%5Coverline%7BYZ%7D%5Cimplies%203a-5%3Da%2B11%5Cimplies%202a-5%3D11%20%5C%5C%5C%5C%5C%5C%202a%3D16%5Cimplies%20a%3D%5Ccfrac%7B16%7D%7B2%7D%5Cimplies%20a%3D8)
A=1/2 bh
1/2 bh=A
h=2A/b
Answer: h=2A/b
Answer:
The time the two planes will meet is 1.43 hours
Step-by-step explanation:
Given;
speed of the first plane in positive direction, = 40 mph
speed of the second plane in negative direction(opposite direction) = -100 mph
distance between the two planes = 200 miles
Let the time the two planes will meet = t
the position of the first plane at this time "t" = 40t
the position of the second plane at this time "t" = -100t
(40t)>--------------------------------<(-100t), this space between them is 200 miles.
Thus, the difference in the distance they traveled before meeting should be equal to 200 miles.
40t - (-100t) = 200
40t + 100t = 200
140t = 200
t = 200 / 140
t = 1.43 hours
Therefore, the time the two planes will meet is 1.43 hours