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Lyrx [107]
3 years ago
6

I can’t figure these three out I keep getting the wrong answers any help would be great....?

Mathematics
2 answers:
vampirchik [111]3 years ago
7 0
25)
(5 - 3)^3 - 3(-3)^2
= 2^3 - 3(9)
= 8 - 27
= -19

answer is D. -19

26)

= 8∛3x + 9∛3x
= 17∛3x

answer is C. 17∛3x

27)
2x^2 - 5x = -2
2x^2 - 5x +2 = 0
(2x - 1)(x -2) = 0
2x - 1; x = 1/2
x - 2 = 0; x = 2

x = 1/2 or x =2

answer is B
x = 1/2 or x =2


allochka39001 [22]3 years ago
5 0
25.) D
26.) C
27.) B
I hope this helps love! :)
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Firdavs [7]

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1 and 101/264

Step-by-step explanation:

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7 0
2 years ago
One number is 8 times another number. The numbers are both positive and have a difference of 70. Find the numbers. Which of the
worty [1.4K]
Let, the first (smaller) number = x
Larger number = 8x
Then, 8x - x = 70
7x = 70
x = 70/7
x = 10
& 8(10) = 80

In short, Your Numbers would be, 10 & 80

Hope this helps!
4 0
3 years ago
A^2(64a^2-3)/3=27-4a^2/4
frutty [35]
The answer is a = 3/4 = 0.75

First get rid of the paranthesis,
{a}^{2} (64 {a}^{2}  - 3) = 64 {a}^{4} -  3 {a}^{2}
Then set the denominators equal:
\frac{ 256 {a}^{4}  - 12 {a}^{2}}{12}  =  \frac{81 - 12 {a}^{2} }{12}
Then remove the denominators and solve:
256 {a}^{4}  - 12 {a}^{2}  = 81 - 12 {a}^{2}
Eliminate -12a^2 by adding 12a^2 to both sides:
256 {a}^{4}  = 81
Take the fourth root of them or take the square root twice:
\sqrt[4]{256 {a}^{4} }  =  \sqrt[4]{81}   \\  4a = 3
Divide both sides by 4:
a =  \frac{3}{4}  = 0.75
7 0
3 years ago
In the figure above AB= 4×+6 and BC=7×+15. if AC=120 , find the length of segment AB.?<br>​
stiks02 [169]

Answer:2x+6

Step-by-step explanation:

5 0
3 years ago
Solve the exponential equation for x. 256=(1/4)^3r+2
Vitek1552 [10]

Answer:

4^4= 4^-1(3r+2)

4^4= 4^(-3r-2)

-3r-2 = 4

-3r= 6

r= -2


-

Step-by-step explanation:


3 0
3 years ago
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