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solong [7]
3 years ago
12

First to answer gets brainlest

Mathematics
1 answer:
Bezzdna [24]3 years ago
7 0

Answer:

B) 279.24

Step-by-step explanation:

line them up the multiple then move the decimal

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3<br>Find the value of a <br>in the equation,(3+4√3)(2-a√3)=-18+2√3​
ankoles [38]

Given:

The equation is:

\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}

To find:

The value of a.

Solution:

We have,

\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}

On simplification, we get

(3)(2)+(4\sqrt{3})(2)+(3)(-a\sqrt{3})+(4\sqrt{3})(-a\sqrt{3})=-18+2\sqrt{3}

6+8\sqrt{3}-3a\sqrt{3}-4a(3)=-18+2\sqrt{3}

6+8\sqrt{3}-3a\sqrt{3}-12a=-18+2\sqrt{3}

(6-12a)+(8-3a)\sqrt{3}=-18+2\sqrt{3}

On comparing both sides, we get

6-12a=-18

-12a=-18-6

a=\dfrac{-24}{-12}

a=2

And,

8-3a=2

-3a=2-8

a=\dfrac{-6}{-3}

a=2

Therefore, the value of a is 2.

3 0
2 years ago
Please complete z2+9z-90=(z-6)(z+?) ...?
notka56 [123]
The answer is:  (z - 6)(z + 15)

z² + 9z - 90 = z*z + 15z - 6z - 6*15 =
                    = (z*z + 15z) - (6z + 6*15) = 
                    = z(z + 15) - 6(z + 15) =
                    = (z - 6)(z + 15)
4 0
3 years ago
Read 2 more answers
Hello please help i’ll give brainliest
MAXImum [283]

Answer:

Just a little puppy

hope this helped

Step-by-step explanation:

8 0
2 years ago
PLEASE HELP QUICKLY 25 POINTS
Natalija [7]

Answer:

○ \displaystyle \pi

Step-by-step explanation:

\displaystyle \boxed{y = 3sin\:(2x + \frac{\pi}{2})} \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{4}} \hookrightarrow \frac{-\frac{\pi}{2}}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 3

<em>OR</em>

\displaystyle \boxed{y = 3cos\:2x} \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 3

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of <em>sine</em>, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of \displaystyle y = 3sin\:2x,in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the <em>sine</em> graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY <em>REALLY</em> ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the <em>sine</em> graph [photograph on the right] is shifted \displaystyle \frac{\pi}{4}\:unitto the right, which means that in order to match the <em>cosine</em> graph [photograph on the left], we need to shift the graph BACKWARD \displaystyle \frac{\pi}{4}\:unit,which means the C-term will be negative, and by perfourming your calculations, you will arrive at \displaystyle \boxed{-\frac{\pi}{4}} = \frac{-\frac{\pi}{2}}{2}.So, the sine graph of the cosine graph, accourding to the horisontal shift, is \displaystyle y = 3sin\:(2x + \frac{\pi}{2}).Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit \displaystyle [-1\frac{3}{4}\pi, 0],from there to \displaystyle [-\frac{3}{4}\pi, 0],they are obviously \displaystyle \pi\:unitsapart, telling you that the period of the graph is \displaystyle \pi.Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the <em>midline</em>. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at \displaystyle y = 0,in which each crest is extended <em>three units</em> beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

7 0
2 years ago
Read 2 more answers
Part C: Of the following choices, which equation is the best fit line for the data
KatRina [158]

Step-by-step explanation:

Part C: Of the following choices, which equation is the best fit line for the data

As we can see from the data, the population size are decreased year by year, so the slope of the line of best fit must be a negative number.

So we have: C and D left.

Let x = 0, year 2005, the population size is 296 around 320, hence, we choose D.

D f(x) = -34x + 320

Part D: What is the predicted population size for the year 2010? How does that compare to the real data? Round to the nearest million.

year 2010, x =5 so let substitute x =5 into  f(x) = -34x + 320

<=> f(x) = -34*5 + 320

= 150 mil

The result is smaller than the real data, (201-150 = 51 mil)

Part E: In what year is the population predicted to go extinct

the population predicted to go extinct when f(x)= 0

<=> -34x + 320 = 0

<=> x  ≈ 9.4

So after 10 years, the the population predicted to go extinct

3 0
3 years ago
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