Answer:
2.16 * (10^-5).
Step-by-step explanation:
5 = -log H+
5 = log (1 / H+)
1/ H+ = 10^5
H+ = 10^-5
In a similar fashion the other brand has H+ of 10^-4.5.
So the difference in hydrogen ion concentration = 10^(-4.5) - 10^(-5)
= 2.16 * (10^-5).
Answer:
5.5
Step-by-step explanation:
It asks for just the Stevens family, so the first sentence is a trick.
Take $49.50 and divide it by $9 an hour. You will end up with 5.5 hours.
Your Question:
<span>Laurie buys four bags of candy with 10 pieces of candy in each bag. Her father then gives her 5 more pieces of candy. Laurie wants to give as much of her candy as she can to each of her six friends, and she wants to make sure they each get an equal number of pieces. How many pieces will be left over, if any, after Laurie gives her friends the candy?
My Answer:
If Laurie has four bags with ten pieces in each bag, and if her father gives her five more pieces, she would have forty-five pieces and if she has six friends and wants to share it equally with six friends. Each friend would get 7 pieces.
My Work:
<span>45 ÷ 6 = 7.5
</span>Hope I helped
♥ James.</span>
The simplified expression for the area of the rectangular table is Three-halves x squared, 3x²/2
<h3>What is the area of the rectangular table?</h3>
Since the carpenter built a square table with side length x. Next, he will build a rectangular table by tripling one side and halving the other.
To find the area of the rectangular table, we know that Area, A = LW where
Now, since the length of the square is x, and the rectangular table has one side of the square tripled and halving the other side .
So,
let
- length of the rectangular table = L = x/2 and
- width of rectangular = W = 3x
So, the area of the rectangular table A = LW
= x/2 × 3x
= 3x²/2
So, the simplified expression for the area of the rectangular table is Three-halves x squared, 3x²/2
Learn more about area of rectangular table here:
brainly.com/question/23807625
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Answer:
If the signs are different subtract the smaller absolute value from the larger absolute value.