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RUDIKE [14]
3 years ago
14

How can u find the answer to 7 over 5 equals x over 15

Mathematics
1 answer:
stepan [7]3 years ago
6 0
Cross cancel 5 and 15 and go from there
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Answer: The answer is the other guys thing

Step-by-step explanation:

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HELP ME. LOOK AT PICTURE
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It would be in the top left corner
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What is the 20th term of the linear sequence?<br><br>1,7,13,19,25
Nimfa-mama [501]

Answer:

115

Step-by-step explanation:

There is a common difference d between consecutive terms, that is

d = 7 - 1 = 13 - 7 = 19 - 13 = 25 - 19 = 6

This indicates the sequence is arithmetic with n th term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 1 and d = 6 , thus

a₂₀ = 1 + (19 × 6) = 1 + 114 = 115

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3 years ago
If tan a= 7/24 find sin a and cos a.. ​
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3 years ago
An external sinusoidal force is applied to an oscillating system which can be modelled by a model spring and a damper. The gener
Anettt [7]

Answer:

The amplitude of the oscillation in this oscillating system, after reaching the steady-state, is 3.984.

Step-by-step explanation:

Assume you know a and b values, which you do not actually need to know to solve the question.

The given general solution of the equation is made up of three terms, namely:

  • A constant value (equal to 4),
  • a cosine term: 3.984cos(2nt-B)
  • a cosine, exponential term: 2.81exp(-8.58t)cos(at + o)

This means that, after a certain time (for large values of time "t"), when the system reaches its <u>steady-state</u>, the following will happen to these parts, respectively:

  • The constant value will remain as 4. It shall not cancel, but it shall not provide any oscillation either, and, in turn, no amplitude nor frequency.
  • The second term will always be a cosine, since it is a periodic function. Its amplitud is "3.984" and its frequency is "2n" radians/second. Its phase is actually "B".
  • This third term is not a periodic functon. It is made up of a periodic function multiplied by an exponential function, whose exponent is negative (for any positive value of time variable "t"). This exponential function approaches to zero when its exponent approaches to minus infinity. So, after a certain time -or, in other words, once the steady-state is eventually reached- the product will be a delimited function (cosine, whose absolute value is always than "1") multiplied by zero. That is, this third term, as a whole, approaches to zero for large, infinite values of time "t".

All in all, once the steady-state is reached, the solution shall remain as:

x = 4+ 3.984cos(2nt-B).

The only oscillation would be that of the cosine term, and its amplitude will be 3.984, an actual value given by the question itself.

4 0
3 years ago
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