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puteri [66]
4 years ago
9

A group of Republicans and Democrats was surveyed and each member was asked whether they liked apple pies or eclairs. 80% of the

Republicans liked apple pie, 55% of the Democrats liked eclairs, and 20% of the Republicans who liked apple pie also liked eclairs. If the number of Republicans who liked both desserts is equal to the number of Democrats who liked eclairs, what is one possible value for the number of members of the group
Mathematics
1 answer:
kirill [66]4 years ago
3 0

Answer:

Any multiple of 71 (i.e. 71, 142, 710, etc)

Step-by-step explanation:

Republicans = R

Democrats = D

Republicans that liked apple pie = 0.80R

Democrats liked eclairs = 0.55D

Republicans who liked apple pie that also liked eclairs = (0.80*0.20)R

If the number of Republicans who liked both desserts is equal to the number of Democrats who liked eclairs, then the following must be true:

(0.8*0.2)R=0.55D\\0.16R=0.55D\\16R=55D

Since the number of Republicans and Democrats must be integers, the least number of members possible is 71 (55+16).

Any value that is a multiple of 71 is a possible value for the number of members of the group

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Answer:

Part 1) csc(\theta)=-\frac{\sqrt{85}}{7}

Part 2) sin(\theta)=-\frac{7}{\sqrt{85}}  or sin(\theta)=-\frac{7\sqrt{85}}{85}

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Step-by-step explanation:

we know that

The angle theta lie on the IV Quadrant

so

sin(θ) is negative

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sec(θ) is positive

csc(θ) is negative

step 1

Find the value of csc(θ)

we know that

1+cot^{2}(\theta)=csc^{2}(\theta)

we have

cot(\theta)=-\frac{6}{7}

substitute

1+(-\frac{6}{7})^{2}=csc^{2}(\theta)

1+\frac{36}{49}=csc^{2}(\theta)

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step 2

Find the value of sin(θ)

we know that

csc(\theta)=\frac{1}{sin(\theta)}

we have

csc(\theta)=-\frac{\sqrt{85}}{7}

therefore

sin(\theta)=-\frac{7}{\sqrt{85}}

or

sin(\theta)=-\frac{7\sqrt{85}}{85}

step 3

Find the value of  tan(θ)

we know that

tan(\theta)=\frac{1}{cot(\theta)}

we have

cot(\theta)=-\frac{6}{7}

therefore

tan(\theta)=-\frac{7}{6}

step 4

Find the value of cos(θ)

we know that

sin^{2}(\theta)+cos^{2}(\theta)=1

we have

sin(\theta)=-\frac{7}{\sqrt{85}}

substitute

(-\frac{7}{\sqrt{85}})^{2}+cos^{2}(\theta)=1

\frac{49}{85}+cos^{2}(\theta)=1

cos^{2}(\theta)=1-\frac{49}{85}

cos^{2}(\theta)=\frac{36}{85}

cos(\theta)=\frac{6}{\sqrt{85}} ------> the cosine is positive

or

cos(\theta)=\frac{6\sqrt{85}}{85}

step 5

Find the value of sec(θ)

we know that

sec(\theta)=\frac{1}{cos(\theta)}

we have

cos(\theta)=\frac{6}{\sqrt{85}}

therefore

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