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3 years ago

Use cavalieri's Principle to calculate the exact of an oblique cylinder with a radius of 10 meters and a height of 11 meters.

2 answers:

8 0

Am I to assume this is for volume? The volume formula for a cylinder...oblique or not...is V = 1/3pi r^2 h. Cavalieri's principle tells us that the formulas for both are the same. So V = 1/3*pi*100*11 and V = 366.67 pi

Zarrin [17]3 years ago

5 0

Answer: Volume of cylinder is 1152.38 m³.

Step-by-step explanation:

Since we have given that

Radius of cylinder = 10 m

Height of cylinder = 11 m

Using Cavalieri's principle , volume of an oblique cylinder is equal to volume of cone.

So, Volume of an oblique cylinder is given by

$V=\frac{1}{3}\pi r^2h\\\\V=\frac{1}{3}\frac{22}{7}\times 10\times 10\times 11\\\\V=1152.38\ m^3$

Hence, Volume of cylinder is 1152.38 m³.

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The lengths of pregnancies in a small rural village are normally distributed with a mean of 264.1 days and a standard deviation

KiRa [710]

Answer:

The range of the 95% data (X) = 238.3 days < X < 289.9 days

Step-by-step explanation:

Given;

mean of the normal distribution, m = 264.1 days

standard deviation, d = 12.9 days

between two standard deviation below and above the mean is 96% of all the data.

two standard deviation below the mean = m - 2d

= 264.1 - 2(12.9)

= 238.3 days

two standard deviation above the mean = m + 2d

= 264.1 + 2(12.9)

= 289.9 days

The middle of the 95% of most pregnancies would be found in the following range;

238.3 days < X < 289.9 days

5 0

3 years ago

write 5 to the 8 power as a quotient of two exponential terms with the same base in four different ways. use negative and/or zer

shusha [124]

Answer:

jhfjdhsuhufhre

Step-by-step explanation:

a) 3x+2(41-5x)=33 as y=41-5x is given

3x+82-10x=33

-7x+82=33

-7x=33-82

-7x=-49 cut the negative signs as its LHS and RHS

x=49/7=7

b)-5x+3(3x-3)=3 as y=3x-3 is given

-5x+9x-9=3

4x-9=3

4x=3+9

x=12/4=3

c)4x+11-5x=9

-x+11=9

-x=9-11

-x=-2 cut the negative signs as its LHS and RHS

x=2

d) 5y+ -5-2y=-11 as x=-5-2y is given

3y+-5=-11

3y=-11+5

3y=-6

y=-6/3=-2

e)-5x-4(2x+1)=35 as y=2x+1

-5x-8x+4=35

3x+4=35

3x=35-4

3x=31

x=31/3

x=10.3

7 0

4 years ago

1/2t + 25; -10 PLEASE HELP

makkiz [27]

You need it to be solved?

4 0

4 years ago

/// WORTH 70 points /// ASAP ////

belka [17]

A community is developing plans for a pool and hot tub. The community plans to form a swim team, so the pool must be built to certain dimensions. Answer the questions to identify possible dimensions of the deck around the pool and hot tub.

Part I: The dimensions of the pool are to be 25 yards by 9 yards. The deck will be the same width on all sides of the pool. Including the deck, the total pool area has a length of (x + 25) yards, and a width of (x + 9) yards.

Write an equation representing the total area of the pool and the pool deck. Use y to represent the total area. Hint: The area of a rectangle is length times width. (1 point)

$y = (x+25)(x+9)$

Rewrite the area equation in standard form. Hint: Use the FOIL method. (1 point)

$y = x^2 + 9x + 25x + 9(25)$

$y = x^2 +34x + 225$

Rewrite the equation from Part b in vertex form by completing the square. Hint: Move the constant to the other side, add to each side, rewrite the right side as a perfect square trinomial, and finally, isolate y. (4 points: 1 point for each step in the hint)

$y-225 = x^2 +34x$

$y-225 + 17^2 = x^2 +34x + 17^2$

$y-225 + 289 = (x+17)^2$

$y = (x+17)^2 - 64$

What is the vertex of the parabola? What are the x- and y-intercepts? Hint: Use your answer from Part a to identify the x-intercepts. Use your answer from Part b to identify the y-intercept. Use your answer from Part c to identify the vertex. (4 points: 1 point for each coordinate point)

The vertex is where the squared term is zero, x=-17 , y =-64, (-17,-64)

The y intercept is y at x=0, so (0,225)

The x intercepts are the zeros; so at x=-25 and x=-9, aka (-25,0), (-9,0)

Graph the parabola. Use the key features of the graph that you identified in Part d. (3 points)

[Plot the points we generated and connect the dots. I'll leave the graphing to you]

In this problem, only positive values of x make sense. Why? (1 point)

<em>x</em> is the width of the pool edge; it must be positive.

What point on your graph shows a total area that includes the pool but not the pool deck? (1 point)

x=0, y=225 i.e. (0,225)

The community decided on a pool area that adds 6 yards of pool deck to both the length and the width of the pool. What is the total area of the pool and deck when x = 6 yards? (2 points)

(9+6)(25+6)=15(31)=465

Part II: A square hot tub will be placed in the center of an enclosed area near the pool. Each side of the hot tub measures 6 feet. It will be surrounded by x feet of deck on each side. The enclosed space is also square and has an area of 169 square feet. Find the width of the deck space around the hot tub, x.

Step 1: Write an equation for the area of the enclosed space in the form y = (side length)2. Hint: Don't forget to add x to each side of the hot tub. (1 point)

$y=(x+6)(x+6)=(x+6)^2$

Step 2: Substitute the area of the enclosed space for y in your equation. (1 point)

169 = (x+6)^2

Step 3: Solve your equation from Part b for x. (3 points)

$x + 6 = \pm \sqrt{169}$

$x = -6
 \pm 13$

$x= 7 \quad \textrm{ or } \quad x= -19$

Step 4: What is the width of the deck around the hot tub? Hint: One of the answers from Part c is not reasonable. (1 point)

Only the positive root works,

x=7 feet

5 0

3 years ago

A psychologist would like to examine the effect of fatigue on mental alertness. An attention test is prepared which requires sub

lianna [129]

Answer:

The calculated value of t= 0.1908 does not lie in the critical region t= 1.77 Therefore we accept our null hypothesis that fatigue does not significantly increase errors on an attention task at 0.05 significance level

Step-by-step explanation:

We formulate null and alternate hypotheses are

H0 : u1 < u2 against Ha: u1 ≥ u 2

Where u1 is the group tested after they were awake for 24 hours.

The Significance level alpha is chosen to be ∝ = 0.05

The critical region t ≥ t (0.05, 13) = 1.77

Degrees of freedom is calculated df = υ= n1+n2- 2= 5+10-2= 13

Here the difference between the sample means is x`1- x`2= 35-24= 11

The pooled estimate for the common variance σ² is

Sp² = 1/n1+n2 -2 [ ∑ (x1i - x1`)² + ∑ (x2j - x`2)²]

= 1/13 [ 120²+360²]

Sp = 105.25

The test statistic is

t = (x`1- x` ) /. Sp √1/n1 + 1/n2

t= 11/ 105.25 √1/5+ 1/10

t= 11/57.65

t= 0.1908

5 0

3 years ago