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erma4kov [3.2K]
3 years ago
14

PLEASE HELPPP ON THIS ONE TOO

Mathematics
1 answer:
andreev551 [17]3 years ago
7 0
I would help you but the image is refusing to load.
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How do I sovle this Please help
elena-s [515]

Answer:

sup

Step-by-step explanation:

8 0
3 years ago
Which of the following values of n will result in a true statement when
ArbitrLikvidat [17]

Answer:

C. n=4

Step-by-step explanation:

got it

6 0
3 years ago
Read 2 more answers
Angles of triangle sand explain how u got each question and answer pls ! ((:
horsena [70]

Answer:

m∠1 = 41°

m∠2 = 85°

m∠3 = 95°

m∠4 = 85°

m∠5 = 36°

m∠6 = 49°

m∠7 = 96°

Step-by-step explanation:

Alright, so to start we have 2 quadrilaterals intersecting to form a triangle, which means that in the shapes with 4 angles, all angles will add up to 360°, while the triangle's angles will add up to 180°

Right off the bat, we can tell that ∠3 and ∠95° are going to be the same, because they're at a perpendicular intersection, which also means that ∠2 and ∠4 will be the same as well

Knowing the ∠3 = 95° means that ∠5 and ∠6 must add up to equal 85°, so that the whole of the triangle equals 180°

Considering that in the first quadrilateral we already have ∠90° and ∠144°, this means that ∠1 and ∠2 have to add up to 126°, to make an even 360° total

If ∠95° is supplementary to ∠2, this means ∠2 = 85°, and since ∠4 and ∠2 are the same, ∠4 also equals 85° - This leaves 41° left for ∠1, and now we can move on to the other quadrilateral

So since we know ∠4 = 85°, and we already have ∠38°, this means that ∠7 and the unmarked angle will add up to equal 237°, so that the entire shape has 360°

Since we know that ∠5 and ∠144° are supplementary, this means ∠5 is equal to 36°, which would make ∠6 = 39°

And lastly we have ∠7, which since ∠6 = 39° this means our unmarked supplementary angle must equal 141° - Now that means that ∠4 + ∠38° + ∠141° = 264° out of 360°, which leaves ∠7 to equal 96°

3 0
3 years ago
Help me answer this question.
neonofarm [45]

Answer:

<h2>8 units²</h2>

Step-by-step explanation:

Let side of the square = a

The , Area of square = a²

Now, Midpoint of Diagonal DB is E

And DE = 2 units

So, DB = 2 DE = 2 × 2 = 4 units

Now, using Pythagoras theorem in ∆ BCD

DB² = DC² + BC²

plug the values

{4}^{2}  =  {a}^{2}  +  {a}^{2}

Collect like terms

{4}^{2}  = 2 {a}^{2}

Evaluate the power

16 = 2 {a}^{2}

Swipe the side of the equation

2 {a}^{2}  = 16

Divide both sides of the equation by 2

\frac{2 {a}^{2} }{ 2 }  =  \frac{16}{2}

Calculate

{a}^{2}  = 8

Therefore, The area of the square is 8 sq.units.

Hope this helps..

Best regards!!

3 0
3 years ago
Rick knows that 1 cup of glue weighs 1/18 pound. He has 2/3 pound of glue. How many cups of glue does he have?
Basile [38]
\begin{array}{ccc}1\ cup&-&\frac{1}{18}\ lb\ (pound)\\\\x\ cup&-&\frac{2}{3}\ lb\ (pounds)\end{array}\ \ \  \ \ \ cross\ multiply\\\\\\\frac{1}{18}x=1\times\frac{2}{3}\\\\\frac{1}{18}x=\frac{2}{3}\ \ \ \ \ \ |multiply\ both\ sides\ by\ 18\\\\18\times\frac{1}{18}x=18\times\frac{2}{3}\\\\x=6\times2\\\\\boxed{x=12}\\\\Answer:He\ has\ 12\ cups\ of\ glue.
6 0
3 years ago
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