Answer:
You are given:
4Fe+3O_2 -> 2Fe_2O_3
4:Fe:4
6:O_2:6
You actually have the same number of Fe on both sides, The same is true for O_2 so yes this equation is properly balanced.
For added benefit consider the following equation:
CH_4+O_2-> CO_2+2H_2O
ASK: Is this equation balanced? Quick answer: No
ASK: So how do we know and how do we then balance it?
DO: Count the number of each atom type you have on each side of the equation:
1:C:1
4:H:4
2:O:4
As you can see everything is balanced except for O To balance O we can simply add a coefficient of 2 in front of O_2 on the left side which would result in 4 O atoms:
CH_4+color(red)(2)O_2-> CO_2+2H_2O
1:C:1
4:H:4
4:O:4
Everything is now balanced.
Step-by-step explanation:
Answer:
really what even is this
Step-by-step explanation:
this makes no sense
Answer: 4
Step-by-step explanation:
The degree is the highest exponent , in which in this problem it is 4. The 3x counts as an exponent of 1 because the variable x is 1, and the 2 counts as an exponent of zero. Which means the degree is 4.
X=12sin(60). X=10.3923...X=6rad3
Answer:
f(9) = - 2/3
Step-by-step explanation:
I don't really know how to answer those but I think I am right
