First things first you have to do write it down which you did
step 2: then you multiply each digit of the binary number by the corresponding power of 2: 1x25 + 0x24 + 1x23 + 1x22 + 0x21 + 1x2 0
step 3: solve the powers: 1x32 + 0x16 + 1x8 + 1x4 + 0x2 + 1x1 = 32 + 0 + 8 + 4 + 0 + 1
step 4: add the numbers written above
32 + 0 + 8 + 4 + 0 + 1 = 45.
So, 45 is the decimal equivalent of the binary number 101101.
The answer is ..........
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hope it helps have a great one! :)
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Hope this helps. If this isn’t the type of answer you were looking for, I apologize.
Answer:
import java.io.*;
import java.util.Scanner;
class divide {
public static void main (String[] args) {
Scanner num=new Scanner(System.in);//scanner object.
int userNum=num.nextInt();
while(userNum>1)//while loop.
{
userNum/=2;//dividing the userNum.
System.out.print(userNum+" ");//printing the userNum.
}
}
}
Input:-
40
Output:-
20 10 5 2 1
Input:-
2
Output:-
1
Input:-
0
Output:-
No Output
Input:-
-1
Output:-
No Output.
Explanation:
In the program While loop is used.In the while loop it divides the userNum by 2 in each iteration and prints the value of userNum.The inputs and corresponding outputs are written in the answer.
