1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vodka [1.7K]
3 years ago
8

Estimate by rounding to the nearest hundred.Show your work.12,846 - 3467​

Mathematics
1 answer:
Rufina [12.5K]3 years ago
3 0

Answer:

9,400

Step-by-step explanation:

12,846 - 3,467 = 9,379

The hundreds digit is 3.

So, you look to the left of the digit and if it is 5 for more you add a number to the 3 and make the rest of the digits 0s. But if it below 5, then you leave the 3 alone and make the rest of the digit going to the right 0s.

Then, your answer is (9,400)

Hope this helps ; )

You might be interested in
2 2/3× 1 1/3 , use an area modle to solve
Ilia_Sergeevich [38]
2 2/3=8/3 and 1 1/3=4/3. 8/3×4/3=32/9. 32/9 as a mixed number is 3 5/9.
4 0
3 years ago
What is the result of converting 60 pounds?
Molodets [167]

Answer:

To kilos? About 132.2. To dollars? Google the exchange.

7 0
2 years ago
It is hard to calculate the volume of a mountain but several estimates put the volume of Mount Everest at around 2,413 cubic kil
scoray [572]

Answer:

About 609,000 Cowboy stadiums could fit inside of Mount Everest

Step-by-step explanation:

we have

The estimate volume of Mount Everest is at around 2,413\ km^{3}

The Dallas Cowboys Stadium has a volume of 140,000,000\ ft^{3}

step 1

Convert ft³ to km³

we know that

1 km=3,280.84 ft

so

140,000,000\ ft^{3}=140,000,000*(1/3,280.84)^{3}=0.003964\ km^{3}

step 2

To find how many Cowboy stadiums could fit inside of Mount Everest, divide the volume of Mount Everest by the volume of the Dallas Cowboys Stadium

2,413/0.003964=608,729

Round to the nearest Thousands

608,729=609,000

The volume of Mount Everest is about 609,000 times greater than the volume of the Dallas Cowboys Stadium

8 0
2 years ago
A ball is thrown vertically upward from the ground with an initial velocity of 111 ft/sec. Use the quadratic function h(t) = −16
ddd [48]

Answer:

t=3.5 seconds

Step-by-step explanation:

Given

h(t) = −16t^2 + 111t + 0

h'(t)= -32t + 111

Maximum height occurs when h(t) = 0 and the ball begins to fall

h(t)= -32t + 111=0

-32t + 111=0

-32t=-111

Divide both sides by -32

t=3.46872

Approximately, t=3.5 seconds

Recall,

Maximum height occurs when h(t) = 0

h(t)= -32t + 111=0

= -32(3.46872)+111

= -110.99904+111

= 0.00096 ft

4 0
2 years ago
Could someone please help ?
blondinia [14]

Answer:

No

Step-by-step explanation:

Put x = 2 into both equations:

For x- 10 = 2-10 = 8 (Not  > 8)

For -0.5x-4 = -0.5*2-4 = -5 (Not < -8)

Hence, the answer is no.

4 0
2 years ago
Other questions:
  • How do you do this question
    5·1 answer
  • Estimate the decimal factors, then multiply to estimate the product. 1. 5.3 rounded to the nearest whole number is ____ . 2. 7.9
    15·2 answers
  • 5th Grade Math Help!​
    12·2 answers
  • Frank ate 12 pieces of pizza and Dave ate 15 pieces. “I ate
    14·1 answer
  • What's the slope and y-intercept?
    6·1 answer
  • If (x + 4) is a factor of polynomial p, which statement must be true?
    6·1 answer
  • Question
    8·1 answer
  • In 2004 kyle was 8 years old . In 2006 kyle was was four year older than his cousin albert. a.how old was albert in 2004. b. in
    7·2 answers
  • Write an algebraic expression for each verbal description.
    9·1 answer
  • An appliance repair person charges $60 for a service call and a labor charge of $30 per hour. What is the rate of change represe
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!