Answer:
rate per month = .01 agreed = r
Luckily they only ask for the first month so it is 0.01 * 20 .
Later months get more complicated and it is like paying off a mortgage with the term unknown but the rate and payment known.
Payment = principal value [ r / {1-(1+r)^-n } ]
100 = 2000 [ .01 / {1 - (1.01)^-n } ]
5 = 1/ {1 - (1.01)^-n }
.2 = 1 - (1.01)^-n
.8 = 1.01^-n
log .8 = -n log 1.01
n = 22.4 months :)
so over the almost two years pay 2240 total :)
<em>* Hopefully this helps:) Mark me the brainliest:)!!!</em>
<em></em>
Answer:
Null hypothesis:
Alternative hypothesis: Not all the means are equal
The best option for this case would be:
H0:μ1=μ2=μ3=μ4
Ha: at least one of the means is different
Step-by-step explanation:
Previous concepts
Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".
The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"
Solution to the problem
For this case we are trying to proof if the mean number of courses taken in a college semester is different for freshmen, versus sophomores, versus juniors, versus seniors.
Based on this case we can set up the following system of hypothesis:
Null hypothesis:
Alternative hypothesis: Not all the means are equal
The best option for this case would be:
H0:μ1=μ2=μ3=μ4
Ha: at least one of the means is different
Answer:
Answer B (proportional)
Step-by-step explanation:
The variable y and x are related by the constant of proportionality "6" in the expression
y = 6 x
Such means that if x adopts whatever value, y is always proportional to that x-value, by the multiplicative factor 6.
y is proportional to x via the proportionality constant (it has to be always a multiplicative constant) "6"
It’s C : -12(3y+1)-1
work:
-12(3y+1)-1
distribute:
(-12)(3y)+(-12)(1)+ -1
-36y+ -12+ -1
combine like terms:
-36y+ -12+ -1
(-36y)+(-12+ -1)
= -36y-13
<em>Answer:</em>
<em>14</em>
<em>Step-by-step explanation:</em>
<em>always subtract the highest number from the lowest and I believe that is your range</em>