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pychu [463]
1 year ago
10

Write the coordinates of the vertices after a reflection over the x-axis. 1072

Mathematics
1 answer:
Liula [17]1 year ago
6 0

The reflection about x-axis results in same x coodinate with oppositive of y coordinate. It can be expressed as,

(x,y)\rightarrow(x,-y)

Determine the coordinates of the vertices after reflection over the x-axis.

Q(6,-8)\rightarrow Q^{\prime}(6,8)R(7,-8)\rightarrow R^{\prime}(7,8)S(7,-5)\rightarrow Q^{\prime}(7,5)T(6,-5)\rightarrow T^{\prime}(6,5)

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A group of employees bought a get well gift for a co worker. The gift costs $46.06. If there are 22 employees in the group, how
Nuetrik [128]
All 22 employees need to pay an equal amount, so $46.06 will be split between 22 people, making this a division question.

$46.06 ÷ 22
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3 years ago
The greatest common factor of 12 and 26 pls explain the steps
Softa [21]
2

12= 2 * 6
26= 2 * 13, gcf is 2




Mark brainliest please mark


Hope this helps you
5 0
3 years ago
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Solve for x and show work need help just stuck on this one ☝
seraphim [82]

Answer:

X=11

Step-by-step explanation:

6 x 11 is 66, after adding 2 its 68. They are equal because they are vertical angles :)

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3 years ago
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Which skier will have a greater potential energy? Skier one is higher then skier two.
masha68 [24]
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3 years ago
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A skier has decided that on each trip down a slope, she will do 2 more jumps than before. On her first trip she did 6 jumps. Der
elixir [45]

The <em>correct answers</em> are:

\Sigma_{n=4}^{12} 6+2(n-1) \\ \\=180

Explanation:

Since she is adding two more jumps every time she goes down hill, this is an arithmetic sequence. The general form of an arithmetic sequence is

a_n=a_1+d(n-1), \\ \text{where } a_n \text{represents the nth term, } a_1 \text{represents the first term, and n represents the term number}

Since we want the number of jumps on her 4th through 12th trips, we will set n in the summation from 4 to 12. n=4 goes at the bottom of Σ and 12 goes at the top, to represent the values we are interested in.

Beside this, we write our general form. The first term is 6 and d, the common difference, is 2. This gives us 6+2(n-1) beside the summation:

\Sigma_{n=4}^{12} 6+2(n-1)

To evaluate this, we substitute the values 4, 5, 6, 7, 8, 9, 10, 11 and 12 in for n, adding all of the values together:

6+2(4-1)+6+2(5-1)+6+2(6-1)+6+2(7-1)+6+2(8-1)+6+2(9-1)+6+2(10-1)+6+2(11-1)+6+2(12-1)

=6+6+6+8+6+10+6+12+6+14+6+16+6+18+6+20+6+22

=180

8 0
3 years ago
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