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Juli2301 [7.4K]
4 years ago
6

3sqrt x - 4=5 solve for x

Mathematics
1 answer:
andrezito [222]4 years ago
3 0
3\sqrt{x}-4=5\ \ \ \ |add\ 4\ to\ both\ sides\\\\3\sqrt{x}=9\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\sqrt{x}=3\ \ \ \ |square\ both\ sides\\\\\boxed{x=9}
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What is the value of x? sin49°=cosx
olasank [31]
Sin+cos=90
49+cos=90
cos=41
3 0
3 years ago
Explain to me in words how you would find the slope of this line and explain answer
Andrews [41]
Answer:
7/3

Explanation:
The slope of the line is equal to the rise/run, or in other words, the number of units the line travels upwards over the number of units the line travels to the right.

We can identify the slope using any two points on the line. Here, we can use the two points that are marked on the picture. The second point is 7 units above the first and 3 units to the right of the first, so the slope of the line is equal to 7/3.

Another way to calculate the slope of the line is the use this formula:

(y2-y1)/(x2-x1)

The first point is at the coordinate (1,-4) and second point is at the coordinate (4,3). When we plug these two coordinates into the equation, we get this:

(y2-y1)/(x2-x1)
->(3-(-4))/(4-1)

When we simply the fraction, we would get 7/3 and that would give us the slope.

I hope this helps!
7 0
3 years ago
Calculate the average rate of change for the graphed sequence from n = 2 to n = 6. (2 points)
Evgesh-ka [11]

Answer:

the answer is c- -3

Step-by-step explanation:

The formula is (14 - 2)/ (2-6)

6 0
3 years ago
Read 2 more answers
Line segment GT contains the point G(−3, 5) and a midpoint at A(1, −4). What is the location of endpoint T?
algol [13]

Imagine you're moving along the segment. Since the midpoint is in the middle of the segment (obviously), it means that when you've traveled from G to A, you're halfway through your journey, along both x and y directions. So, let's break the problem in two and analyze both directions.


Along the x axis, you've moved from -3 to 1, so you moved 4 units forward. This means that you have 4 units still to go, and your journey will end at coordinate 5.


Similarly, along the y axis, you've moved from 5 to -4, so you moved 9 units downward. This means that you have 9 units still to go, and your journey will end at coordinate -13.


So, the coordinates of the endpoint are T = (5,-13)


If you prefer a more analyitical approach, simply write the definition of the midpoint and solve it for the coordinates of T.


We have G = (-3, 5) and T = (x_T,y_T). The midpoint is computed as


A = \left( \frac{-3+x_T}{2},\frac{5+y_T}{2} \right) = (1, -4)


So, you have the equations


\frac{-3+x_T}{2} = 1,\qquad \frac{5+y_T}{2} = -4


Multply both equations by 2 to get


-3+x_T = 2,\qquad 5+y_T = -8


Move the constants to the right hand sides to get


x_T = 5,\qquad y_T = -13

8 0
3 years ago
If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c
dolphi86 [110]

Given:

(ax+2)(bx+7)=15x^2+cx+14

And

a+b=8

Required:

To find the two possible values of c.

Explanation:

Consider

\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}

So

\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}

And also given

a+b=8---(2)

Now from (1) and (2), we get

\begin{gathered} a+\frac{15}{a}=8 \\  \\ a^2+15=8a \\  \\ a^2-8a+15=0 \end{gathered}a=3,5

Now put a in (1) we get

\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}

When a=5 and b=3, we have

\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}

Final Answer:

The option D is correct.

31 and 41

8 0
1 year ago
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