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Solnce55 [7]
4 years ago
10

I really need help on this one. Help please

Mathematics
1 answer:
ddd [48]4 years ago
6 0
COULD YOU BE Y GIRLFRIEND IF I ANSWER?

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Factor by using the perfect-square trinomial formula. <br><br> 100x^2+20x+1
a_sh-v [17]
To factor first multily 100 and 1 and get 100

then find what 2 numbers multiply to get 100 and add to get 20

the numbers are 10 and 10

so
split the center term up
100x^2+10x+10x+1
group
(100x^2+10x)+(10x+1)
undistribute
(10x)(10x+1)+(1)(10x+1)
undistribute/reverse distributive property
(10x+1)(10x+1)
(10x+1)^2
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3 years ago
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Select THREE expressions equivalent to –81x + 27.
Ivahew [28]

Answer:

A, C, and D

Step-by-step explanation:

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3 years ago
10-kg bag of cherries for $8<br><br> ___ per kg
Sophie [7]
$8.00/10 kg equals $0.80/kg
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3 years ago
Babies born after 40 weeks gestation have a mean length of 52.2 centimeters (about 20.6 inches). Babies born one month early hav
Sveta_85 [38]

Answer:

a) Z = -2.88

b) Z = -0.96

c) 40 weeks gestation babies

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

a. Find the standardized score (z-score), relative to all U.S. births, for a baby with a birth length of 45 cm.

Here, we use \mu = 52.2, \sigma = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 52.2}{2.5}

Z = -2.88

b. Find the standardized score of a birth length of 45 cm. for babies born one month early, using 47.4 as the mean.

Here, we use \mu = 47.4, \sigma = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 47.4}{2.5}

Z = -0.96

c. For which group is a birth length of 45 cm more common?

For each group, the probability is 1 subtracted by the pvalue of Z.

Z = -2.88 has a lower pvalue than Z = -0.96, so for Z = -2.88 the probability 1 - pvalue of Z will be greater. This means that for 40 weeks gestation babies a birth length of 45 cm is more common.

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3 years ago
What is 1,450,000 in scientificnotation
geniusboy [140]

Answer:

The answer is 1.45*10^6

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3 years ago
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